dahano
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The discussion focuses on determining the angle of projection and speed of a projectile described by the trajectory equation y = √3 x - (1/5)x². Participants emphasize the importance of calculus, specifically the derivative dy/dx, which represents the tangent of the angle of projection (θ) at the point of projection (x = 0). The formula for range, R = u²Sin(2θ)/g, is also highlighted as a crucial component in solving for the initial speed (u) of the projectile. Clear steps involve calculating the gradient at the origin and applying the range formula to find the required values.
PREREQUISITESStudents studying physics, particularly those focusing on kinematics and projectile motion, as well as educators seeking to enhance their teaching methods in these topics.
dahano said:I've tried some wild attempts but they landed me no where :-
Qwertywerty said:Please post these attempts .
However I still give a hint :
What does dy/dx represent ?
What is the formula for Range ?
Sorry to ask a stupid question but what do you mean by point? Can you please show me how would it be solved?andrevdh said:The angle of projection can be found from the gradient of the graph at what point?
dahano said:I figured out the formula of range as: u2Sin2(theta)/g
Can you tell me that how would it be done further?
Please attach your working for this.dahano said:I figured out the formula of range as: u2Sin2(theta)/g