Finding the angle of projection and its speed in 2D Kinetics

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SUMMARY

The discussion focuses on determining the angle of projection and speed of a projectile described by the trajectory equation y = √3 x - (1/5)x². Participants emphasize the importance of calculus, specifically the derivative dy/dx, which represents the tangent of the angle of projection (θ) at the point of projection (x = 0). The formula for range, R = u²Sin(2θ)/g, is also highlighted as a crucial component in solving for the initial speed (u) of the projectile. Clear steps involve calculating the gradient at the origin and applying the range formula to find the required values.

PREREQUISITES
  • Understanding of 2-Dimensional Kinematics
  • Basic calculus, specifically differentiation
  • Familiarity with projectile motion equations
  • Knowledge of the range formula R = u²Sin(2θ)/g
NEXT STEPS
  • Study the principles of projectile motion in physics
  • Learn how to differentiate functions to find slopes
  • Explore the derivation and application of the range formula in projectile motion
  • Practice solving problems involving trajectories and angles of projection
USEFUL FOR

Students studying physics, particularly those focusing on kinematics and projectile motion, as well as educators seeking to enhance their teaching methods in these topics.

dahano
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Homework Statement

: The trajectory of a projectile in a vertical plane is y = √3 x - (1/5)x2, where x and y are respectively horizontal and vertical distances of the projectile from the point of projection. Find the angle of projection and speed of projection.[/B]

Homework Equations

: 2-Dimensional Equations and maybe calculus.[/B]

The Attempt at a Solution

: Honestly, I can't even understand that how do I begin with this question. I've tried some wild attempts but they landed me no where :-( Can you please guide me with the solution to this question? [/B]
 
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dahano said:
I've tried some wild attempts but they landed me no where :-

Please post these attempts .

However I still give a hint :

What does dy/dx represent ?
What is the formula for Range ?
 
The angle of projection can be found from the gradient of the graph at what point?
 
I figured out the formula for Ran
Qwertywerty said:
Please post these attempts .

However I still give a hint :

What does dy/dx represent ?
What is the formula for Range ?

I figured out the formula of range as: u2Sin2(theta)/g

Can you tell me that how would it be done further?
 
andrevdh said:
The angle of projection can be found from the gradient of the graph at what point?
Sorry to ask a stupid question but what do you mean by point? Can you please show me how would it be solved?
 
dahano said:
I figured out the formula of range as: u2Sin2(theta)/g

Can you tell me that how would it be done further?

Here - dy/dx at x = 0 represents tan(θ) ( where θ is angle of projection ) .

Find range , and then using formula for range find u .
 
Last edited:
What does the trajectory or path of the projectile look like?
What is the equation which describes the path or trajectory?
 
dahano said:
I figured out the formula of range as: u2Sin2(theta)/g
Please attach your working for this.
 

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