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Finding the area of trapezoid area question

  1. Mar 18, 2013 #1
    (double integral) cos((y-x)/(y+x))dA
    Where the double integral is over the region with points (1, 0), (2, 0), (0, 2), and (0, 1).
    I think the trapezoid is enclosed by
    y+x = 1
    y+x = 2
    y=0
    x=0
    How can I use this? Thanks
     
  2. jcsd
  3. Mar 18, 2013 #2
    Hello nemesest, for this problem, you can make a substitution u=y-x, v=y+x, compute the Jacobian, and express the integral in terms of u and v (don't forget that the final representation of the integral must involve the Jacobian). The result is (3/2)*sin1. Hope that helps :)
     
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