Finding the bandwidth of an FM signal

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The discussion centers on determining the bandwidth of a frequency-modulated (FM) signal defined by A(t)=A0sin[2πfct+Δfsin(2πfmt)/fm]. Participants question the values of fc and fm, suggesting a possible mix-up, with fc likely being 88.1 MHz and fm as 3.5 kHz. The calculation of bandwidth is noted to require the frequency deviation, Δω, which is not provided in the problem statement. Additionally, the relationship between normalized bandwidth and frequency deviation is emphasized for accurate computation. The conversation highlights the importance of clarity in parameters for solving FM signal bandwidth effectively.
tai man
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Homework Statement


Consider the frequency-modulated (FM) signa A(t)=A0sin[2πfct+Δfsin(2πfmt)/fm] , where fc = 3.5 kHz, fm = 88.1 MHz. What is the bandwidth of the signal? [Note: You may take sin≅ and cos≅1 for x (in radian) << 1.]

Homework Equations


A(t)=A0sin[2πfct+Δfsin(2πfmt)/fm]

The Attempt at a Solution


for finding bandwidth, isn't it (fc+fm)-(fc-fm)?
 
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tai man said:

Homework Statement


Consider the frequency-modulated (FM) signa A(t)=A0sin[2πfct+Δfsin(2πfmt)/fm] , where fc = 3.5 kHz, fm = 88.1 MHz. What is the bandwidth of the signal? [Note: You may take sin≅ and cos≅1 for x (in radian) << 1.]

Homework Equations


A(t)=A0sin[2πfct+Δfsin(2πfmt)/fm]

The Attempt at a Solution


for finding bandwidth, isn't it (fc+fm)-(fc-fm)?
I think the question has mixed up fc and fm, which should be probably be 88.1MHz and 3.5kHz respectively. It also does not specify the deviation, which you need to find the bandwidth.
 
I agree with post #2. Also, the required bandwidth depends on the (constant) frequency deviation Δω; then a bandwidth BW can be computed from a normalized bandwidth curve BW/2Δω vs. β.
 

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