Finding the Center of Mass of a Hemisphere

Click For Summary
SUMMARY

The discussion focuses on calculating the center of mass of a hemisphere using calculus. The volume of an elemental disc is defined as Rdθ (cos θ)(πR²cos² θ), where R is the radius of the hemisphere. The arc length is derived from the projection of R onto the θ=0 plane, which is Rcos(θ), leading to the correct formulation for the volume element. A request for a visual sketch to aid understanding highlights the complexity of the topic.

PREREQUISITES
  • Understanding of calculus, specifically integration techniques.
  • Familiarity with the concept of center of mass in physics.
  • Knowledge of spherical coordinates and their applications.
  • Basic skills in sketching geometric shapes for visualization.
NEXT STEPS
  • Study the derivation of volume elements in spherical coordinates.
  • Learn about the application of integration in finding the center of mass.
  • Explore visual aids and software for geometric visualization, such as GeoGebra.
  • Review examples of similar problems involving the center of mass of different shapes.
USEFUL FOR

Students studying physics or engineering, particularly those focusing on mechanics and calculus, as well as educators seeking to explain the concept of center of mass in three-dimensional shapes.

ritwik06
Messages
577
Reaction score
0

Homework Statement


Center of Mass of a hemisphere

http://www.goiit.com/templates/default/images/chapters/center_mass/image064.gif
http://www.goiit.com/templates/default/images/chapters/center_mass/image068.gif
Why is volume of elemental disc = [tex]Rd\theta (cos \theta) (\pi R^{2}cos^{2} \theta)[/tex] and not

[tex]Rd\theta (\pi R^{2}cos^{2}\theta)?[/tex]
 
Last edited by a moderator:
Physics news on Phys.org
Because the arc length is measured from the [itex]\theta=0[/itex] plane (yz plane) to the plane rotated through an angle [itex]d\theta[/itex], So the radius of the arc is the projection of R onto the [itex]\theta=0[/itex] plane which is [itex]Rcos(\theta)[/itex] and so the arc length is [itex]Rcos(\theta)d\theta[/itex].
 
gabbagabbahey said:
Because the arc length is measured from the [itex]\theta=0[/itex] plane (yz plane) to the plane rotated through an angle [itex]d\theta[/itex], So the radius of the arc is the projection of R onto the [itex]\theta=0[/itex] plane which is [itex]Rcos(\theta)[/itex] and so the arc length is [itex]Rcos(\theta)d\theta[/itex].

I don't get it. Could you please take some of ur precious time out, just to draw a very rough sketch in paint? Please!
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
6
Views
4K
Replies
8
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
2
Views
2K
  • · Replies 19 ·
Replies
19
Views
4K
Replies
16
Views
2K