Finding the Center of Mass of a Hemisphere

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ritwik06
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Homework Statement


Center of Mass of a hemisphere

http://www.goiit.com/templates/default/images/chapters/center_mass/image064.gif
http://www.goiit.com/templates/default/images/chapters/center_mass/image068.gif
Why is volume of elemental disc = [tex]Rd\theta (cos \theta) (\pi R^{2}cos^{2} \theta)[/tex] and not

[tex]Rd\theta (\pi R^{2}cos^{2}\theta)?[/tex]
 
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Because the arc length is measured from the [itex]\theta=0[/itex] plane (yz plane) to the plane rotated through an angle [itex]d\theta[/itex], So the radius of the arc is the projection of R onto the [itex]\theta=0[/itex] plane which is [itex]Rcos(\theta)[/itex] and so the arc length is [itex]Rcos(\theta)d\theta[/itex].
 
gabbagabbahey said:
Because the arc length is measured from the [itex]\theta=0[/itex] plane (yz plane) to the plane rotated through an angle [itex]d\theta[/itex], So the radius of the arc is the projection of R onto the [itex]\theta=0[/itex] plane which is [itex]Rcos(\theta)[/itex] and so the arc length is [itex]Rcos(\theta)d\theta[/itex].

I don't get it. Could you please take some of ur precious time out, just to draw a very rough sketch in paint? Please!