A meter stick is 200 g. A mass of 1 kg is placed in 20 cm, and another mass of 5 kg is placed in 100 cm.
So the diagram will be like:
Why do we have to include M2? And why is the mass of M2 is 200g? Isn't the whole meter stick weight 200g, and ithe mass of M2 should be lighter because it is just a point on the meter stick.
The Attempt at a Solution
Center of Mass = [(1)(0.2) + (0.2)(0.5) + (5)(1)] / (1+0.2+5) = 0.8548