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## Homework Statement

A nylon tennis string on a racket is under a tension of 225 N. If its diameter is 0.97 mm, by how much is it lengthened from its untensioned length of 29.6 cm?

Li= 29.6cm =.296 m

r= 4.85e-4 m

A= 7.389811319e-7

F= 225 N

E= Young's Modulus for Nylon= 5 x 10^9

Solving for deltaL

## Homework Equations

A=pi(r)^2

F= E (delta L/Li) A

## The Attempt at a Solution

I've found the area and tried using the equation above but did not get a correct answer. I may well have messed up the calculations because that equation confuses me a little and I seem to be algebraically challenged this fine morning.

All my incorrect answers so far are:

14.5e-8 cm

7.470483757e-8 cm

14.506204362e-7 cm

7.470483757e-6 cm (the last three answers came from the equation above)

Any help is greatly appreciated! Thank you!