A nylon tennis string on a racket is under a tension of 225 N. If its diameter is 0.97 mm, by how much is it lengthened from its untensioned length of 29.6 cm?
Li= 29.6cm =.296 m
r= 4.85e-4 m
F= 225 N
E= Young's Modulus for Nylon= 5 x 10^9
Solving for deltaL
F= E (delta L/Li) A
The Attempt at a Solution
I've found the area and tried using the equation above but did not get a correct answer. I may well have messed up the calculations because that equation confuses me a little and I seem to be algebraically challenged this fine morning.
All my incorrect answers so far are:
7.470483757e-6 cm (the last three answers came from the equation above)
Any help is greatly appreciated! Thank you!