Finding the Constant for Solving a 2nd Order Differential Equation

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Homework Help Overview

The discussion revolves around solving a second-order differential equation of the form d²x/dt² = -(k/m)x - g, with specific initial conditions provided. The participants are exploring methods to find the constant involved in the solution.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss various methods for solving the differential equation, including direct integration and the concept of quadrature. There are questions about the initial conditions and how they relate to the constants of integration. Some participants also question the interpretation of the term sqrt(u² - 2gh) as a constant.

Discussion Status

The discussion is active, with participants offering different approaches and seeking clarification on the methods suggested. There is no explicit consensus on the best method to use, but several lines of reasoning are being explored.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the methods they can use or the information they can provide. The initial conditions and the interpretation of certain terms are also points of discussion.

zeithief
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can any1 help me solve this? d2x/dt2 = -(k/m)*x -g
at x= 0, t=0, v=sqrt(u^2-2gh)

what is x?? can show the steps?
 
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This DE can be solved by direct integration. After calculating \frac{dx}{dt} = v(t) and x(t), use the initial conditions to get the constants of integration.

P.S. x(t) is a function of position in time.
 
One of the reasons we ask that people show what they have already done is so we will have a better idea of what kind of help you need and what kinds of suggestions you would understand. I can think of several ways of solving this but I'm not sure what "tools" you have to use.

The method radou is suggesting is called "quadrature". Since t does not explicitely appear in the equation, you can eliminate it. Let v= dx/dt. The d2x/dt2= dv/dt= (dv/dx)(dx/dt)= vdv/dx. That is, the original equation can be written as a first order equation.
Now we have vdv/dx= -(k/m)x- g. In fact, that is separable and, so, easily integrable: vdv= (-(k/m)x- g)dx so (1/2)v2= -(k/2m)x2- 2x+ C (the v2 is the reason for the name "quadrature"). Once you have found v as a function of t, integrate dx/dt= v to find x.

But that is not the method I would use. This is a linear d.e. with constant coefficients. I has "characteristic equation" r2= -(k/m) which has roots r= \pm i\sqrt{k/m}. The general solution to the associated homogeneous equation is
x(t)= C_1cos(\sqrt{k/m}t)+ C_2sin(\sqrt{k/m}t)
Now you need to find a "specific" solution to the entire equation. Since the "non-homogeneous part" is the constant, -g, I would suggest assuming y is a constant: y(t)= A, and seeing if you can pick A to make the equation true. Does any of that make sense? That was what I meant by "not sure what "tools" you have to use".
By the way, is "sqrt(u^2-2gh)" simply a constant?
 
ya sqrt(u^2- 2gh) is a constant how should i go about solving it to satisfy this condition?
 
Do what I suggested before. Assume y= A, a constant, and plug that into the equation. What does A have to be in order for the equation to be true?
 

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