Finding the Critical Value of IVP: 'Given DE

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SUMMARY

The discussion centers on identifying the critical value of the initial value problem (IVP) defined by a differential equation (DE) and its boundary behavior as time approaches infinity. The critical value, referred to as the separatrix, distinguishes between solutions that exhibit positive growth and those that exhibit negative growth. The participants confirm that this critical value is not universally determined by setting the constant of integration, c, to zero, but rather depends on the specific characteristics of the DE and the initial conditions. Understanding this concept is crucial for analyzing the stability and behavior of solutions to differential equations.

PREREQUISITES
  • Understanding of initial value problems (IVP) in differential equations.
  • Familiarity with the concept of separatrices in dynamical systems.
  • Knowledge of the behavior of solutions to first-order differential equations.
  • Basic skills in solving differential equations and interpreting their solutions.
NEXT STEPS
  • Research the concept of separatrices in more detail, particularly in relation to nonlinear differential equations.
  • Explore the methods for determining critical values in various types of differential equations.
  • Learn about stability analysis of solutions to initial value problems.
  • Investigate the role of the constant of integration in the context of differential equations and its impact on solution behavior.
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Mathematics students, educators, and researchers focusing on differential equations, particularly those interested in stability analysis and the behavior of solutions in initial value problems.

tylerc1991
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Homework Statement



This is more theoretical than anything, but let's say that a problem is stated like:

Consider the IVP: 'given DE'; y(0) = y_0

find the value of y_0 that separates the solutions that grow positively from those that grow negatively as t -> infinity.

The Attempt at a Solution



(1) Is there a name for this particular value of y_0? Is it called the critical value?

(2) is the critical value always found by setting c = 0? (where c is the constant of integration found when solving the IVP)?

Thank you for your help and let me know if I am unclear with anything.
 
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The way I have seen this is:

In a more generalized form in first order (y' = f(x, y)), if there exists a solution that serves as a boundary between two classes of solutions to the differential equation that behave differently, then that solution is called a separatrix. I don't think I have seen a term for the initial value, but it combined with the equation would give you the solution that served as the boundary anyway. Seeing as how picking a different value of x would give a different initial value somewhere along the separatrix, potentially, I think the solution would be more important from a theoretical standpoint.
 

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