1. The problem statement, all variables and given/known data This problem is regarding electric circuits. The diagram in the book is a parallel circuit. The voltage of a single battery is 1.5V and there are three resistors. The two resistors that are in parallel are 6 ohms and 12 ohms. The third resistor is 8 ohms and the resistance in the battery is negligible.: I apologize for the crude diagram. The question I got stuck is asking what the current flowing through the 6 ohm resistor is. 2. Relevant equations The equivalent resistance (Req) of the two-resistor parallel combination is: 1/Req= 1/6 + 1/12 Req= 4ohms The total current flowing through the battery is: I=V/R I=1.5/(4+8) I=0.125A 3. The attempt at a solution My prof actually wrote the answer of the question in my textbook, but I cannot understand how or why he did what he did. His answer was thus: I (of 6 ohms) = (12/18) x 0.125 =0.083A I thought I=V/R, so this does not make sense to me. Can someone please explain why he did this the way he did? (Classes are finished and I cannot get a hold of him before the exam). Any help would be greatly appreciated. Regards, Michelle.