Finding the current on each resistor

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Homework Help Overview

The discussion revolves around a circuit analysis problem involving Kirchhoff's laws to find the current through resistors R1, R2, and R3. Participants are examining the application of these laws to derive equations based on the given circuit diagram.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply Kirchhoff's laws to set up equations but questions their correctness after comparing with provided solutions. Other participants suggest the need for an additional equation from a junction to resolve the system of equations.

Discussion Status

Participants are actively engaging in the problem, with some providing guidance on the necessary equations. There is a recognition of the need for two independent loop equations and one junction equation, indicating a productive direction in the discussion.

Contextual Notes

There is mention of confusion regarding the number of equations needed and the correct application of Kirchhoff's laws. The original poster expresses uncertainty about their calculations and the correct interpretation of the circuit setup.

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Homework Statement


[PLAIN]http://img297.imageshack.us/img297/7053/96217079.jpg

given this circuit find the current on R1,R2 and R2

Homework Equations


I = V/R

The Attempt at a Solution



i applied kirchhof's law and I have this:

36 - 5*I - I1*4 = 0
36 - 5*I + 20 - 2*I2 - 14 = 0
20 - 2*I2 - 14 + I1*4 = 0

and i find I1 = 66/19 which is wrong
the book says
I1 = 1.10 A
I2 = 5.21 A
I = 6.32 A

what am i doing wrong?
 
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Hi kliker! :smile:

(try using the X2 tag just above the Reply box :wink:)
kliker said:
I applied kirchhof's law and I have this:

36 - 5*I - I1*4 = 0
36 - 5*I + 20 - 2*I2 - 14 = 0
20 - 2*I2 - 14 + I1*4 = 0

The circuit only has two independent loops, so you can only get two independent equations from it.

The third Kirchhoff equation you need is for one of the junctions. :smile:
 
tiny-tim said:
Hi kliker! :smile:

(try using the X2 tag just above the Reply box :wink:)The circuit only has two independent loops, so you can only get two independent equations from it.

The third Kirchhoff equation you need is for one of the junctions. :smile:


hi, thanks for the answer

if we say I = I1 + I2 and take the first two equations

then we will have

36 -5*I1 - 5*I2 - 4*I1 = 0
36 - 5*I1 -5*I2 +20 - 2*I2 - 14 = 0

36 - 5*I2 - 9*I1 = 0
36 - 5*I1 - 7*I2 + 6 = 036 - 5*I2 - 9*I1 = 0
42 - 5*I1 - 7*I2 = 0

then by solving the equations I found the desired results

thanks a lot

Ps: what's the x2 tag? I can't find it
 
Hi kliker! :smile:

(just got up :zzz: …)
kliker said:
…then by solving the equations I found the desired results

:biggrin: Woohoo! :biggrin:
Ps: what's the x2 tag? I can't find it

Press the "QUOTE" button or the "Advanced Reply" button, and you get to the Reply to Thread page, with loads of useful tags to play with, above the box where you enter your text. :wink:
 

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