Finding the curve to minimize a functional

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SUMMARY

The discussion focuses on finding the curve y(x) that minimizes the functional I[y] = integral(y'² - y², x, 0, 1) using Euler's equation. The user correctly identifies the functional form f{y, y'; x} = y'² - y² and derives the necessary partial derivatives. Applying Euler's equation leads to the differential equation -2y - 2y'' = 0, resulting in the general solution y = A cos(x) + B sin(x). By applying the boundary conditions y(0) = 0 and y(1) = 1, the final curve is determined to be y(x) = sin(x)/sin(1).

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Esran
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Homework Statement



Find the curve y(x) that passes through the endpoints (0,0) and (1,1) and minimizes the functional I[y] = integral(y'2 - y2,x,0,1).

Homework Equations



Principally Euler's equation.

The Attempt at a Solution



We choose f{y,y';x} = y'2 - y2. Our partial derivatives are:

df/dy = -2y
df/dy' = 2y'

Euler's equation gives:

df/dy - d/dx(df/dy') = 0
-2y - 2y'' = 0

The general solution for this differential equation is:

y = A cos(x) + B sin(x)

To find A and B, we use our constraint that y(0) = 0 and y(1) = 1. Our curve is then y(x) = sin(x)/sin(1).

Have I done this problem correctly? If not, where did I go wrong?
 
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I don't see anything wrong with your method.
 

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