Question 6.9 Taylor: Classical Mechanics

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SUMMARY

The discussion focuses on solving the second-order differential equation derived from the Euler-Lagrange equation for the functional ∫(y'² + yy' + y²) dx, specifically for the path from the origin O to point P(1,1). The equation simplifies to y'' = y, with one known solution y = e^x, which does not satisfy the boundary conditions. The correct solution is identified as y = sinh(x)/sinh(1), which meets the required conditions. Additionally, the general solution is expressed as a linear combination of two solutions: y = A1 e^x + A2 e^(-x).

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Lujz_br
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Homework Statement


Hello, I solved others but not 6.9:
Find the equation of the path joining the origin O to point P(1,1) in the xy plane that makes the integral ∫(y'2 +yy' + y2) dx stationary.
∫ from O to P. y' = dy/dx

Homework Equations


I need use ∂f/∂y = d/dx (∂f/∂y') (euler-lagrange equation) with f = y'2 +yy' + y2
∂f/∂y = y' + 2y
∂f/∂y' = 2y' + y

and d/dx (∂f/∂y') = 2 y'' + y', go to euler-lagrange equation we get:
y' + 2y = 2 y'' + y'
this is equivalent to:
y'' = y (eq 1)

y = ex is solution of eq. 1, but it don't fit (0,0) and (1,1)
I see the solution at final of the book: y = senh(x)/senh(1)
Ok, is solution of eq. 1 and fit points (0,0) and (1,1).

There are any thing more? I feel I don't get good answer without look at the final of the book.
Thanks! Luiz

 
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You have a second-order differential equation, so you should have two solutions. You found one. What's the other one? The general solution will be a linear combination of the two solutions.
 
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Ok, 1st is y = A1 ex 2nd is y = A2 e-x and general solution is y = A1 ex + A2 e-x which go to y = senh(x)/senh(1).
Ok, remember this (two solutions) is fine way to get the right answer... :)
 

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