A proton, which is the nucleus of a hydrogen atom, can be modeled as a sphere with a diameter of 2.4 fm and a mass of 1.67e-27 kg. Determine the density of the proton.
As far as I know, the only required formula is D = m/v
The Attempt at a Solution
Well my attempt looks like this:
(2.4)^3*pi*(4/3) = 57.90583579 fm^3
Used google to convert that into kilometers, and got 57.905835791 (femtometer^3) = 5.79058358e-44 meter^3.
Divided 1.67e-27 kg by 5.79058358e-44 meter^3.
Got 2.883992566e16 but apparently, it's wrong.
Any suggestions guys?