Finding the density of a hydrogen proton

[AryRezvani]

Homework Statement

A proton, which is the nucleus of a hydrogen atom, can be modeled as a sphere with a diameter of 2.4 fm and a mass of 1.67e-27 kg. Determine the density of the proton.

Homework Equations

As far as I know, the only required formula is D = m/v

The Attempt at a Solution

Well my attempt looks like this:

(2.4)^3*pi*(4/3) = 57.90583579 fm^3

Used google to convert that into kilometers, and got 57.905835791 (femtometer^3) = 5.79058358e-44 meter^3.

Divided 1.67e-27 kg by 5.79058358e-44 meter^3.

Got 2.883992566e16 but apparently, it's wrong.

Any suggestions guys?

 

[TSny]

Hello, AryRezvani.

Note they give you the diameter, not the radius of the proton.

 

[AryRezvani]

Hello, AryRezvani.

Note they give you the diameter, not the radius of the proton.

Ahh... Feeling rather stupid now.

Thanks.

 

[TSny]

That's not stupid, just a little oversight...(I'm doing things like that a lot in my old age ).