# Finding the density of a hydrogen proton

## Homework Statement

A proton, which is the nucleus of a hydrogen atom, can be modeled as a sphere with a diameter of 2.4 fm and a mass of 1.67e-27 kg. Determine the density of the proton.

## Homework Equations

As far as I know, the only required formula is D = m/v

## The Attempt at a Solution

Well my attempt looks like this:

(2.4)^3*pi*(4/3) = 57.90583579 fm^3

Used google to convert that into kilometers, and got 57.905835791 (femtometer^3) = 5.79058358e-44 meter^3.

Divided 1.67e-27 kg by 5.79058358e-44 meter^3.

Got 2.883992566e16 but apparently, it's wrong.

Any suggestions guys?

TSny
Homework Helper
Gold Member
Hello, AryRezvani.

Note they give you the diameter, not the radius of the proton.

Hello, AryRezvani.

Note they give you the diameter, not the radius of the proton.

Ahh...... Feeling rather stupid now.

Thanks.

TSny
Homework Helper
Gold Member
That's not stupid, just a little oversight...(I'm doing things like that a lot in my old age ).