Setting up an Uncertainty Problem

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Homework Help Overview

The problem involves calculating the minimum uncertainty in the velocity of a proton within the nucleus of a gold atom, given the nucleus's radius of approximately 6 femtometers (fm). The context is rooted in quantum mechanics, specifically the uncertainty principle.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the interpretation of the 6 fm measurement, debating whether it represents a radius or a diameter. There are attempts to clarify the implications of this distinction on the uncertainty calculation.

Discussion Status

The discussion is ongoing, with participants providing feedback on each other's interpretations. Some guidance has been offered regarding the correct understanding of the nucleus's dimensions, but no consensus has been reached on the implications for the uncertainty calculation.

Contextual Notes

There are indications of confusion regarding the representation of the nucleus's size and its effect on the uncertainty in position. Participants are exploring how to appropriately apply the uncertainty principle in this context.

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Homework Statement


A proton is known to lie within the nucleus of a gold atom. The radius of a gold nucleus is approximately 6 fm. What is the minimum uncertainty in the proton’s velocity [you may treat the problem as one-dimensional and you should express your answer as a fraction of c].

Homework Equations


ΔxΔp ≥ ħ/2

The Attempt at a Solution


I think I got this, but Chegg is showing up weird inconsistent answers. I just want to make sure my logic is sound:

So since we can treat this one dimensionally, we know that the proton lies within a 6fm range. For simplicity, we can (in our imaginations) draw a 6 fm line and put a point on the center. On that center, our uncertainty of the position of the proton is ± 3 fm. So our Δx should be 3fm instead of 6 fm!

The rest of the work is rather simple, I just want to make sure I'm setting this up properly.
 
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The 6 fm represents the radius of the nucleus.
 
TSny said:
The 6 fm represents the radius of the nucleus.

Not very helpful. I think my work shows that I understand this.
 
talrefae said:
Not very helpful. I think my work shows that I understand this.
No, it shows you thought the 6fm was a diameter.
 
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Not that it would make a difference to this order of magnitude calculation, but if someone gave me a proton in a one-dimensional box that extends, say, from zero to 12 fm and asked "where is the proton?", I would say "somewhere between zero and 12 fm". So in such situations, I consider the position uncertainty to be the entire range in which the particle can be without me knowing any better.
 
haruspex said:
No, it shows you thought the 6fm was a diameter.

You're 100% right. Thanks for that!
 

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