Finding the Direction of Resultant Vector: A Vector Addition Problem

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SUMMARY

The discussion focuses on calculating the resultant vector from three given angles: a = 20.8°, b = 54.0°, and c = 29.7°. The resultant vector's magnitude is determined to be 1.9 units. To find the direction of the resultant vector counterclockwise from the positive x-axis, participants emphasize using trigonometric functions to calculate the x and y components, followed by applying the arctangent function to derive the angle. A graphical sketch is recommended for clarity in visualizing the vector components.

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The question is find the resultant of the vectors shown in the figure below. (Take a = 20.8°, b = 54.0° and c = 29.7°.)

I got the resultant vector to be 1.9units, it also tells me to find the direction counterclockwise from the positive x-axis. I'm not sure how to do that, is it asking me the degrees? I'm just confused what the question is asking for.
 
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sycho2 said:
The question is find the resultant of the vectors shown in the figure below. (Take a = 20.8°, b = 54.0° and c = 29.7°.)

I got the resultant vector to be 1.9units, it also tells me to find the direction counterclockwise from the positive x-axis. I'm not sure how to do that, is it asking me the degrees? I'm just confused what the question is asking for.
Yes, once you find the magnitude of the resultant vector, usually by using trig to find the x and y components of each vector, summing those components into the Rx and Ry components of the resultant, then the angle of the resultant vector is the angle whose tangent is Ry/Rx. Be sure to draw a rough graphical sketch, and properly detrmine its angle as measured ccw from the positive x axis.
 
Um, what "figure below"?
 

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