# Finding the distance in an acceleration problem (different)

1. Mar 10, 2010

### SoConfused__

1. The problem statement, all variables and given/known data
You are travelling at 60km/h when all of a sudden you see a pink elephant which is 0.125km down the road. Your car can slow down at a rate of -5.0m/s^2. If it takes you 20 m of distance to react and hit the brake, how far will you be from the elephant when you stop?

2. Relevant equations
D = (V1+V2/2)t
A = V2-V1/T

3. The attempt at a solution
To be honest, I really don't even know where to begin with this problem. I don't even know how to visualize this.

Okay so the break is hit when it's 0.105km away. (0.125 - 20).

Time = Velocity / Acceleration
= 60/-0.03 (5m = 0.005km/s = 0.03km/h)
= 200 hours?

Just from this point I know it's wrong. I can't continue further because I'm already starting off on the wrong foot.

I need some guidance in the RIGHT direction, please & thank you!

Also, the answer is supposed to be 77m.

2. Mar 10, 2010

### ehild

Take care of the units and dimensions. The acceleration is not 5 m, neither 0.005 km/s, and 0.005 km/s is not 0.03 km/h.

The best thing first when you start to solve a problem to convert all units to Si ones: m, s, kg, and so on.

ehild

3. Mar 11, 2010

### chronos12

You need to use the equations for motion with constant acceleration.

Time is the variable you do not know, so use an equation that does not include time: v2=v02+2a(x-x0)

The final velocity (the v on the left side of the equation) will be zero (because you will be stopped). You want to solve for (x-x0) and then try to work it out from there using the distance you travel before braking and the distance you start from the elephant. Also, convert the 60km/hr to meters/second.

I worked the problem and came up with 77m.