- #1

HarshK

- 12

- 0

## Homework Statement

I am investigating a scenario where a pendulum with a bob attached is released from an angle and pushes a box to a certain distance. My goal is to find the coefficient of friction between the box and the surface it moved on.

I have measurements for:

- mass of the bob (

**125 grams**)

- mass of the box (

**267.3 grams**)

- length of the pendulum (

**27 cm**)

- distance the box moved from its initial position (

**3.2 cm**)

- angle of release (

**30 degrees above the x-axis**)

## Homework Equations

- 1/2(m)(v^2) = mgh

- Vf = sqrt(2*g*h)

- m1+v1=m2+v2

- h = L(1-cos(theta))

- Ff=μFN

## The Attempt at a Solution

0.27(1-cos(30))=

**h**= 3.62 cm

sqrt (2*9.8*0.0362) =

**Vf**= 0.84 m/s (speed before hitting the box)

(0.125)(0.84)=(0.2673)(v2),

**v2**= 0.33 m/s (speed of the block)

(9.8)(0.2673) =

**FN**= 2.62 N

I don't know where to go from here. If you could help me or point me in the right direction, I would greatly appreciate it, Thanks!