(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

An accelerometer measures the acceleration of an object every 0.050s.

The initial velocity is 0 m/s.

The initial distance is 0 m/s.

The accelerations at the times (in m/s^2):

a(0.000) = 5

a(0.050) = 7

a(0.100) = 10

a(0.150) = 15

a(0.200) = 15

a(0.250) = 15

a(0.300) = 5

a(0.350)= -10

a(0.400)= -10

If possible, estimate the distance traveled by the object from t=0s to t=0.400s.

2. Relevant equations

[tex]

v_{ave} = \Delta x / \Delta t

[/tex]

[tex]

a_{ave} = \Delta v / \Delta t

[/tex]

[tex]

x = x_0 + v_0 t + (1/2) a t^2

[/tex]

[tex]

v^2 = v_0^2 + 2 a \Delta x

[/tex]

3. The attempt at a solution

I tried to find the slopes of the a(t) graph by having v(.025)=(7-5)/(.05-0) and v(.075)=(10-7)/(.1-.05). Then I tried to find the slope of the v(t) graph by x(.05)=(v(.075)-v(.025))/(.075-.025)=400m which is, of course, extremely high for the times and accelerations.

Another approach I thought of was to add up all of the recorded accelerations, divide them by the number of accelerations found, and use this average acceleration in

[tex]

x = x_0 + v_0 t + (1/2) a t^2

[/tex]

as

[tex]

x = 0 + 0 + (1/2) (average acceleration) (total time)^2

[/tex]

Are these correct approaches? Are there any other ways to do this that are more accurate?

Thanks.

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# Homework Help: Finding the distance with an acclerometer and a timer

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