1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Finding the Electric Field at the Midpoint of two rings

  1. Jul 26, 2016 #1
    1. The problem statement, all variables and given/known data
    Hello,

    Two 10-cm-diameter charged rings face each other, 20 cm apart. The left ring is charged to -22 nC and the right ring is charged to +22 nC . What is the magnitude of the electric field E⃗ at the midpoint between the two rings?

    2. Relevant equations

    E = Kq/r^2
    K = 8.99 * 10^9

    3. The attempt at a solution

    Find the electric field at the midpoint caused by each individual plate, then using the principle of superposition to add them.

    E(tot) = |E(1)| + |E(2)|

    |E(1)| = K (22nC)/0.1^2
    |E(2)| = K (22nc)/0.1^2

    |E(1)| + |E(2)| = E {since E(1) and E(2) are the same}

    E(tot) = E = 2 * K (22nC)/0.1^2 = 395560 N/C

    However, the answer I got is wrong. I have also tried E = 0 N/C in case I was not supposed to take the magnitudes. This is also incorrect.

    Could anyone lend me a hand?
     
  2. jcsd
  3. Jul 26, 2016 #2

    haruspex

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    That would be the field 10cm from a point charge of 22nC.
    The charge here is distributed around a ring (not a plate). At the centre of each ring there is no field induced by that ring since the fields due to the charges around the ring point in all directions through the centre and, by symmetry, cancel.
    Consider a small portion of one ring, length rdθ, carrying charge q, where r is the ring's radius. And consider a point P distance x from the centre of the ring, along the axis of the ring. How far is P from the charge q? What is the strength of the field at P due to the charge q? In what direction does that field point?

    Alternatively, you may have already been taught a formula for the axial field due to one ring, in which case all you have to do is double it for the second ring.
     
  4. Jul 26, 2016 #3
    Thank you! I got it now :)
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted