Finding the Electric Field at the Midpoint of two rings

  • #1
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Homework Statement


Hello,

Two 10-cm-diameter charged rings face each other, 20 cm apart. The left ring is charged to -22 nC and the right ring is charged to +22 nC . What is the magnitude of the electric field E⃗ at the midpoint between the two rings?

Homework Equations


[/B]
E = Kq/r^2
K = 8.99 * 10^9

The Attempt at a Solution



Find the electric field at the midpoint caused by each individual plate, then using the principle of superposition to add them.

E(tot) = |E(1)| + |E(2)|

|E(1)| = K (22nC)/0.1^2
|E(2)| = K (22nc)/0.1^2

|E(1)| + |E(2)| = E {since E(1) and E(2) are the same}

E(tot) = E = 2 * K (22nC)/0.1^2 = 395560 N/C

However, the answer I got is wrong. I have also tried E = 0 N/C in case I was not supposed to take the magnitudes. This is also incorrect.

Could anyone lend me a hand?
 

Answers and Replies

  • #2
haruspex
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K (22nC)/0.1^2
That would be the field 10cm from a point charge of 22nC.
The charge here is distributed around a ring (not a plate). At the centre of each ring there is no field induced by that ring since the fields due to the charges around the ring point in all directions through the centre and, by symmetry, cancel.
Consider a small portion of one ring, length rdθ, carrying charge q, where r is the ring's radius. And consider a point P distance x from the centre of the ring, along the axis of the ring. How far is P from the charge q? What is the strength of the field at P due to the charge q? In what direction does that field point?

Alternatively, you may have already been taught a formula for the axial field due to one ring, in which case all you have to do is double it for the second ring.
 
  • #3
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Thank you! I got it now :)
 

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