Finding the equation of a system involving dashpots and mass on wheels

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SUMMARY

The discussion focuses on deriving the equations of motion for a mechanical system involving dashpots and mass on wheels, with input force denoted as 'u'. The key equations presented include 0=k1x+mx"+k2(x-y)+b(x'-y') and 0=b(y'-y')+k2(y-x)+k3*y+u. Participants emphasize the importance of treating the dashpot as a resistor and the mass as an inductor, drawing parallels between mechanical and electrical systems to simplify analysis. The input 'u' is clarified as a velocity input rather than a force input, highlighting critical distinctions in the system's dynamics.

PREREQUISITES
  • Understanding of Newton's second law (F=ma)
  • Familiarity with mechanical systems involving dashpots and masses
  • Basic knowledge of electrical circuit analogies in mechanical systems
  • Proficiency in solving differential equations
NEXT STEPS
  • Study the dynamics of mechanical systems with dashpots and springs
  • Learn about the mathematical modeling of mechanical systems using differential equations
  • Explore the concept of analogies between electrical circuits and mechanical systems
  • Investigate the role of damping in mechanical systems and its effects on motion
USEFUL FOR

Students and professionals in mechanical engineering, physics, and applied mathematics who are involved in modeling and analyzing dynamic systems, particularly those incorporating damping elements like dashpots.

lzh
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Homework Statement


consider the mechanical system below. Find the equation depicting the system. u is the input force. sorry for the poor picture, I had to draw it on my tablet...
http://img685.imageshack.us/img685/1043/ogataprob.png

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Homework Equations


F=ma


The Attempt at a Solution


I'm not sure how to treat the dashpot in parallel with the mass. I came up with the following system of equations:

0=k1x+mx"+k2(x-y)+b(x-y)
0=b(x-y)+k2(x-y)+k3(y-u)
 
Last edited by a moderator:
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hi lzh! :smile:

according to http://en.wikipedia.org/wiki/Dashpot" , the resistance is porportional to the speed :wink:
 
Last edited by a moderator:
hi!
oops I mistyped...
0=k1x+mx"+k2(x-y)+b(x'-y')
0=b(x'-y')+k2(x-y)+k3(y-u)
 
I can't tell you anything for sure since I haven't done these problems in years. The way I used to check out the mechanical "circuit" when I got overwhelmed was based on my electrical knowledge. Your dashpot is a resistor and your mass is an inductor. Always use this as a double check when you're unsure of a mechanical setup. The info for the electrical setup will always be more easy to find.

EDIT: Looking at your equations of motion now though, I think you have it or are close. There is no need to fudge with the circuit. Just find X and Y based on input u.
 
Last edited:
0=k1x+mx"+k2(x-y)+b(x'-y')
0=b(y'-y')+k2(y-x)+k3*y+u

after some more modification, but I'm still unsure...
 
For starters:

Note that u would be a velocity input, not a force input.

b is by' - it has no contact with the velocity at x

and I think for m it is m(y"-x")

I haven't checked your equations yet, so patience please
 

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