js14 said:find the equation of an ellipse whose foci is (0,4)?
Im not really sure of how to begin with this. Its actually a graph problem and it only gives the foci. can someone help me with this?
The general equation for an ellipse is (x-h)^2/a^2 + (y-k)^2/b^2 = 1, where (h,k) represents the center of the ellipse and a and b represent the length of the semi-major and semi-minor axes, respectively.
The center of an ellipse can be found by using the formula (h,k), where h is the x-coordinate of the center and k is the y-coordinate of the center. These values can be determined by finding the midpoints of the major and minor axes of the ellipse.
The semi-major axis is the longer half of an ellipse, while the semi-minor axis is the shorter half. These values determine the shape and size of the ellipse.
The length of the semi-major axis a can be found by measuring the distance from the center of the ellipse to the farthest point on the ellipse. The length of the semi-minor axis b can be found by measuring the distance from the center to the closest point on the ellipse.
Yes, an ellipse can have negative values for a and b. This indicates that the ellipse is elongated in a specific direction, either horizontally or vertically, and the center of the ellipse is shifted from the origin.