Finding the extension of a spring

  • Thread starter Thread starter Dustinsfl
  • Start date Start date
  • Tags Tags
    Extension Spring
Click For Summary

Homework Help Overview

The discussion revolves around determining the extension of a spring when a weight is suspended from it. The problem involves a spring with a stiffness of 4000 N/m and a weight of 50 N, alongside a harmonic force applied to the system.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between the weight and spring extension, questioning the units and clarity of the original problem statement. Some participants emphasize the importance of specifying units and the conditions under which the extension is measured.

Discussion Status

The discussion is ongoing, with participants providing guidance on the need for clarity in the problem statement and the significance of initial conditions. There is a recognition of the equilibrium condition where the forces must balance, but no consensus on the exact interpretation of the question has been reached.

Contextual Notes

Participants note the lack of explicit information regarding the timing of the extension measurement and the initial conditions of the mass. The original poster's question about the extension is seen as potentially ambiguous, leading to varied interpretations of the problem.

Dustinsfl
Messages
2,217
Reaction score
5

Homework Statement


A weight of ##50## N is suspended from a spring of stiffness ##4000## N/m and is subjected to a harmonic force of amplitude ##60## N and frequency ##6## Hz.

Homework Equations

The Attempt at a Solution


Since ##W = mg = 50##, we have that the suspended mass, ##m = 5.10204##, and we know that ##f = \frac{\omega}{2\pi} = 6## so ##\omega = 12\pi##. The harmonic forcing term is then
$$
F(t) = 60\cos(12\pi t)
$$
and our equation of motion is
$$
\ddot{x} + \frac{4000}{5.10204}x = \frac{60}{5.10204}\cos(12\pi t).
$$
Solving the transient and steady solution, we obtain
$$
x(t) = A\cos(28t) + B\sin(28t) - 0.0184551\cos(12\pi t)
$$
How do I determine the extension of spring from the suspended mass? This value would then be ##x(0) = x_0##. Additionally, I will assume any motion starts from rest so ##\dot{x}(0) = 0## which leads to ##B = 0## and ##A## can be defined as ##x_0 - \frac{F_0}{k - m\omega^2}## where ##\omega = 12\pi## and ##F_0 = 60##
$$
x(t) = (x_0 + 0.0184551)\cos(28t) - 0.0184551\cos(12\pi t)
$$
Would the extension of the spring simply be, ##F = kx## where ##F = 50## so
$$
x_0 = \frac{F}{k} = \frac{1}{80}\mbox{?}
$$
 
Physics news on Phys.org
1/80 what? Lightyears? Attometers? Quoting units is very important in physics ...

You problem statement is missing a question so it is difficult to understand exactly what the problem you wish to solve is.

For the equilibrium point, the forces of gravity and from the spring need to cancel. Which leads to the equation yoy are quoting in the end.
 
What is the question here? What are you trying to do?
 
Orodruin said:
1/80 what? Lightyears? Attometers? Quoting units is very important in physics ...

You problem statement is missing a question so it is difficult to understand exactly what the problem you wish to solve is.

For the equilibrium point, the forces of gravity and from the spring need to cancel. Which leads to the equation yoy are quoting in the end.
What is the extension of the spring? The units are trivial to solve for N/(N/m).
 
nasu said:
What is the question here? What are you trying to do?

What is the extension of the spring?
 
Dustinsfl said:
What is the extension of the spring? The units are trivial to solve for N/(N/m).

The point is that units are important. I am perfectly aware of how they propagate but you need to provide your values with units throughout. Your answer is not 1/80, it is 1/80 m. Just saying 1/80 has no meaning as a length.

Extension of the spring when? Based on the information you have given it is oscillating. Do you need to find it as a function of time or the average extension? This is why we ask you to provide the problem exactly as stated word by word.

I believe you have answered the question about the equilibrium extension yourself already.
 
  • Like
Likes   Reactions: Dustinsfl
Orodruin said:
The point is that units are important. I am perfectly aware of how they propagate but you need to provide your values with units throughout. Your answer is not 1/80, it is 1/80 m. Just saying 1/80 has no meaning as a length.

Extension of the spring when? Based on the information you have given it is oscillating. Do you need to find it as a function of time or the average extension? This is why we ask you to provide the problem exactly as stated word by word.

I believe you have answered the question about the equilibrium extension yourself already.

I know it is oscillating. The question just says "the extension of the spring due to the suspended weight"
 
What Orodruin is getting at is: where is the mass located to start with (at t = 0), what is the velocity of the mass initially (at t = 0), and what is the force as a function of time (starting from t = 0)?

Chet
 
Chestermiller said:
What Orodruin is getting at is: where is the mass located to start with (at t = 0), what is the velocity of the mass initially (at t = 0), and what is the force as a function of time (starting from t = 0)?

Chet

##x(0) = x_0## not giving, ##\dot{x}(0) = \dot{x}_0## not giving but I am assuming it is zero, and the forcing function ##F(t)## is in the statement. I believe finding the springs extension is going to be the initial position.
 
  • #10
For the initial conditions you assumed, it looks like you did the problem correctly. So what is it you want us to help you with?

Chet
 
  • #11
Chestermiller said:
For the initial conditions you assumed, it looks like you did the problem correctly. So what is it you want us to help you with?

Chet

I just wanted to know how to find the extension of the spring due to the suspended mass. I think it is just ##x = \frac{50}{4000}## so I was checking whether my though is correct.
 
  • #12
Dustinsfl said:
I just wanted to know how to find the extension of the spring due to the suspended mass. I think it is just ##x = \frac{50}{4000}## so I was checking whether my though is correct.
With no additional information, that's what I would have used for the initial extension.

Chet
 
  • Like
Likes   Reactions: Dustinsfl
  • #13
Dustinsfl said:
I just wanted to know how to find the extension of the spring due to the suspended mass. I think it is just ##x = \frac{50}{4000}## so I was checking whether my though is correct.
If this is the only question, then all the formulas you wrote there, with the exception of last one, are irrelevant. You must admit that your post was a little confusing.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
1K
Replies
4
Views
1K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
17
Views
3K
Replies
16
Views
2K
Replies
9
Views
2K
Replies
7
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
4
Views
3K
Replies
6
Views
1K