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Homework Help: Finding the first-order taylor polynomial

  1. Jan 21, 2009 #1
    1. The problem statement, all variables and given/known data

    Basically, I have a differential equation. One of the elements of it is...

    F(P) = 0.2P(1 - (P/10))

    And I need to replace it with it's first-order Taylor polynomial centered at P=10.

    3. The attempt at a solution

    I haven't done Taylor polynomial stuff in over a year so I went and looked it up...as near as I could tell, an FOTP of an equation was the equation plus the derivative of that equation times (x - a). Is this accurate?

    If so, this is fairly simple, as I can find the derivative of F(P) as 0.2 - 0.04P. but what do I do with the (x - a) part? I think for my purposes it would be (x - P), but still, how do I treat this?
     
  2. jcsd
  3. Jan 21, 2009 #2

    quasar987

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    You do not take the FOTP of an equation, you take the FOTP of a function. Here the function is F and the variable is P.

    In general, if f is a function and we write x the variable on which it depends, its FOTP at the point a is the function

    [tex]x\mapsto f(a)+f'(a)(x-a)[/tex]

    In your case, f=F, x=P and a=10.

    I leave to you the pleasure of finding the FOTP of F at 10
     
  4. Jan 21, 2009 #3
    The value a is the point you are expanding around. In your case a = 10. You expand to first order so the differential equation can be solved by analytical methods. Let x = P. Then the equation is

    F(x) = 0.2x(1 - (x/10))

    The first order expansion is then

    [tex]F(x)\approx F(10) + F'(10)(x-10)[/tex]
     
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