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Finding the force of magnetic field lines

  1. Mar 22, 2009 #1
    1. The problem statement, all variables and given/known data

    A wire carrying 15 A of current has a length of 17 cm in a magnetic field of 0.80 T. The force on a current-carrying wire in a uniform magnetic field can be found using the equation F = BIL sin θ. Find the force on the wire for each of the following angles between the wire and the magnetic field lines. ( (a) 90° )

    2. Relevant equations

    F = BIL
    Sin = Opposite/Hypotenuse
    17 cm / 100 = .17 m

    3. The attempt at a solution

    F = 15*.17*.8*sin(90)
    = 1.8238 N
     
    Last edited: Mar 22, 2009
  2. jcsd
  3. Mar 23, 2009 #2

    Redbelly98

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    Looks like you did the multiplication wrong.

    F = 15*.17*.8*sin(90) is correct.
     
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