Finding the force of magnetic field lines

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SUMMARY

The discussion focuses on calculating the force exerted on a current-carrying wire in a magnetic field using the formula F = BIL sin θ. Given a wire with a current of 15 A and a length of 17 cm in a magnetic field of 0.80 T, the force is calculated for an angle of 90°. The correct calculation yields a force of 1.8238 N, confirming the application of the formula is accurate.

PREREQUISITES
  • Understanding of the formula F = BIL for magnetic force calculations
  • Knowledge of basic trigonometry, specifically the sine function
  • Familiarity with units of measurement, particularly converting centimeters to meters
  • Basic principles of electromagnetism
NEXT STEPS
  • Study the effects of varying angles on the force using F = BIL sin θ
  • Explore the implications of different magnetic field strengths on force calculations
  • Learn about the applications of magnetic forces in real-world scenarios, such as electric motors
  • Investigate the relationship between current, magnetic fields, and force in different configurations
USEFUL FOR

Students in physics, educators teaching electromagnetism, and anyone interested in understanding the principles of magnetic forces on current-carrying conductors.

itsmarasilly
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Homework Statement



A wire carrying 15 A of current has a length of 17 cm in a magnetic field of 0.80 T. The force on a current-carrying wire in a uniform magnetic field can be found using the equation F = BIL sin θ. Find the force on the wire for each of the following angles between the wire and the magnetic field lines. ( (a) 90° )

Homework Equations



F = BIL
Sin = Opposite/Hypotenuse
17 cm / 100 = .17 m

The Attempt at a Solution



F = 15*.17*.8*sin(90)
= 1.8238 N
 
Last edited:
Physics news on Phys.org
Looks like you did the multiplication wrong.

F = 15*.17*.8*sin(90) is correct.
 

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