Finding the general form of a Struve Function

Click For Summary

Homework Help Overview

The discussion revolves around the Struve function, specifically focusing on the series expansion given in the problem statement. Participants are exploring the expression of this series and its relation to known functions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to derive a general expression for the series, noting similarities to the expansion of Sin[x]. They express uncertainty about the denominator's structure, which involves products of squared odd numbers. Another participant suggests considering the factorial of odd integers as a potential approach.

Discussion Status

Participants are actively engaging with the problem, with some offering insights and suggestions. There is acknowledgment of confusion and realization about the notation required for calculations in Mathematica. The discussion is ongoing, with no explicit consensus reached yet.

Contextual Notes

The original poster mentions a specific question from their homework and has provided a Mathematica file for further exploration. There is an indication of potential constraints related to the notation used in the software.

eclayj
Messages
20
Reaction score
0
I am given the following series which the problem states is known as a Struve function:

x -x^3/(1^2 3^2)+x^5/(1^2 3^2 5^2)-x^7/(1^2 3^2 5^2 7^2) + ...

I am trying to figure out the expression of the series. I have thought about this for some time. I am sure I am missing the obvious. It looks a little like the expansion of Sin[x] in powers of x. Anyway, I have worked at the numerator as follows:

-1^k x^(2k+1)

I cannot figure out for the life of me an expression that will give the denominator of the terms in the series (odd numbers squared and multiplied, i.e. the first term's denominator is one squared, then the next term has the denominator one squared times three squared, etc.).

If anyone could help me think about this it would be greatly appreciated. Thanks so much! I have attached a .nb file to run in Mathematica if it helps. It is the second question.

-EJ
 

Attachments

Physics news on Phys.org
What about (2k+1)!^2?
 
Wow. Pretty obvious. Maybe I shouldn't be doing so late at night. Thank you very much!
 
Also didn't realize that you need two factorial symbols "!" rather than the usual one symbol for Mathematica to recognize and properly calculate the equation.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
904
Replies
2
Views
1K
  • · Replies 40 ·
2
Replies
40
Views
5K
Replies
2
Views
2K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K