Finding the gravitational force over a flat infinite sheet

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SUMMARY

The discussion focuses on calculating the gravitational force exerted by a flat infinite sheet using Gauss' Law and integral calculus. The user is attempting to derive the gravitational force by integrating the mass density σ over concentric rings, but struggles with the mathematical formulation, particularly in incorporating the differential element dr. Key insights include the necessity of considering only the vertical component of the force and correctly defining the area element as an annulus with area 2πrdr. The correct approach involves integrating from a radius R to infinity while applying the gravitational force formula F=Gσ2πr*m/Z².

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  • Understanding of Gauss' Law in electrostatics and gravitation
  • Familiarity with integral calculus, particularly in multiple dimensions
  • Knowledge of gravitational force equations, specifically F=Gm1m2/r²
  • Concept of mass density (σ) and its application in gravitational contexts
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  • Study the application of Gauss' Law in gravitational fields
  • Learn how to set up and evaluate integrals in polar coordinates
  • Explore the concept of mass density and its implications in physics
  • Review the derivation of gravitational force for different geometries, including sheets and spheres
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Students in physics or engineering, particularly those studying gravitational fields, integral calculus, and applications of Gauss' Law in real-world scenarios.

Phantoful
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Homework Statement


2nno2Tj.png


Homework Equations


F=ma
F=Gm1m2/r2
Gauss' Law?

The Attempt at a Solution


I'm not sure if I should be using Gauss' Law for this question, because I've never heard of it or learned about it. I'm currently taking multi-variable calculus (gradients, vectors, etc.). From what I know, the gravitational force should be found using an integral from R to infinity for the area of the plane... but I'm not sure what to do from there.

G*∫((mσ)/(Z^2))*dA from R to ∞?
 

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You can't "dA from R". Decide what your variable of integration is and use that in the range, in the expression for the force and in the expression for the infinitesimal element.
 
Okay, I'm starting to visualize it now, but I'm not sure how to put it into mathematics. I want to find the gravitational force for each concentric circle that has mass σπ(r2-R2) because V*σ=Msheet, and just using geometry the distance between the mass and the circles would be (r2+Z2)½, here's where I am:

wI5H0X1.png


However, I know that it's not correct mathematically because I'm not sure how to include dr, which I know is supposed to be in here. How can I make it a part of my integral? Or am I approaching this incorrectly?
 

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The dr is included by putting the correct mass of the infinitesimal ring which is σ2πrdr.
 
Note also that only the vertical component of the force due to the ring is to be considered.
 
grzz said:
The dr is included by putting the correct mass of the infinitesimal ring which is σ2πrdr.
grzz said:
Note also that only the vertical component of the force due to the ring is to be considered.
I'm not sure how to visualize it this way, but what you're saying is that my equation (inside the integral) should be ((Gσ2πr*m)/Z2)*dr? I used the second equation from #2 in my original post, m being the mass of the point and G being the constant. Why is the equation for circumference instead of area used? I made the integral from R to ∞, which I believe is correct, right?
 
Phantoful said:
Why is the equation for circumference instead of area used?
Because the element has to consist of a region for which d is roughly constant. That makes it an annulus of internal radius r and external radius r+dr. That has area 2πrdr.
 

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