Finding the hange in inetic energy

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SUMMARY

The discussion centers on calculating the change in kinetic energy for a 1609 kg car traveling at 11.9 m/s that comes to a complete stop after hitting a tree. The initial kinetic energy (KE) is calculated using the formula KE = 1/2 mv², resulting in 113925.245 J. Since the car comes to rest after the impact, the final kinetic energy is 0 J. Therefore, the change in kinetic energy is 113925.245 J.

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  • Familiarity with units of energy (Joules)
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sylavel
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Homework Statement


A 1609 kg car has a speed of 11.9 m/s when it hits a tree. The tree doesn't move and the car comes to rest.
Find the change in kinetic energy of the car. Answer in units of J.


Homework Equations


KE=1/2mv^2



The Attempt at a Solution


Okay so like I am not completely sure where to go here...
I started out in finding the kinetic energy
KE=1/2(1609)(11.9)^2=113925.245
Any help would be super awesome.
 
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sylavel said:

Homework Statement


A 1609 kg car has a speed of 11.9 m/s when it hits a tree. The tree doesn't move and the car comes to rest.
Find the change in kinetic energy of the car. Answer in units of J.


Homework Equations


KE=1/2mv^2



The Attempt at a Solution


Okay so like I am not completely sure where to go here...
I started out in finding the kinetic energy
KE=1/2(1609)(11.9)^2=113925.245
Any help would be super awesome.

OK You found the Kinetic energy for before impact.

What is the KE after impact? What is v?

What is the difference?
 

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