Finding the incline of the slope

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    Incline Slope
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Homework Help Overview

The problem involves determining the incline of a slope based on the forces acting on a skier. The original poster has calculated the skier's acceleration and is attempting to assess whether the slope exceeds 45 degrees using a specific equation related to sine and cosine functions.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of forces and equations to analyze the incline, with some suggesting the application of trigonometric relationships and others questioning the original poster's understanding of the terms used.

Discussion Status

The discussion is ongoing, with participants providing feedback on the original poster's calculations and suggesting alternative approaches. There is a mix of confirmations and corrections regarding the equations being used, indicating a collaborative effort to clarify the problem.

Contextual Notes

There are mentions of potential misunderstandings regarding the definitions of weight and mass, as well as the need for accurate equations to analyze the forces involved. The original poster expresses uncertainty about their calculations and the validity of their results.

happyjoe
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Hey everyone, I'm new here, and just wanted to say hi first. Second, I was wondering if anyone would so kind as to help me with this problem.

Homework Statement



An 80kg skiier has a force of 200N exerted on him down the slope. Now I've already found the acceleration of 2.5m/s^2, however, now i need to work out whether the slop is more than 45 degrees. I understand I need to use the gsincos equation, but I'm getting nowhere in using it. If anyone could explain how I'm able to find whether the slope is greater than 45 degrees or not, then i'd really appreciate it. Thanks


Homework Equations



Not sure if I am on the right track but.

Sincos = a/g = 2.5/9.8

The Attempt at a Solution

 
Last edited:
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looks like you are on the right track.

you can also solve this by using the forces. weight^2=net force^2+normal force^2 for inclines.

EDIT: sorry had made a mistake in the formula.
 
Last edited:
pooface said:
looks like you are on the right track.

you can also solve this by using the forces. weight^2=net force^2+normal force^2 for inclines.

EDIT: sorry had made a mistake in the formula.


Thanks for your help! :D I am not sure if I am doing it right still though as when I do the first equation of sincos = acceleration/gravity I get 0.255, and when I do the second equation that you gave me I get weight ^2 = 614,656kg, net force ^2 = 40,0000 + normal force^2 = 40000. The answer I keep getting is 7.68 which may be correct, but I am not sure if it is.

Thanks! :D
 
do arcsin of a/g:

Check your equation in the notes again. I don't know what this 'sincos' is.

kg is not a weight quantity, it is mass. To convert kg to weight in Newtons you must first multiply the mass in kg by acceleration due to gravity which is 9.81m/s^2.

The second formula is the pythagorean formula. The forces create a triangle.
see this diagram. http://www.cheops-pyramide.ch/khufu-pyramid/great-pyramid/inclined-plane.gif

Gm is the weight, N is normal force.
 

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