Finding the initial velocity of a vector

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Homework Help Overview

The discussion revolves around finding the initial velocity of an object thrown at an angle of 23 degrees, covering a distance of 8.59 m. The subject area pertains to kinematics and projectile motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss breaking the motion into horizontal and vertical components. There is an attempt to clarify the independence of horizontal and vertical motions. Some participants express confusion regarding the implications of this independence.

Discussion Status

The discussion is ongoing, with some participants offering insights on how to approach the problem by considering the time of flight and the relationship between distance and speed. There is no explicit consensus yet, as participants are exploring different aspects of the problem.

Contextual Notes

Participants are working within the constraints of the problem statement and the kinematic equations provided. There is an indication of uncertainty regarding the application of these equations to find the initial velocity.

HelloImAsh
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Homework Statement


An object that is thrown covers a distance of 8.59 m. If the angle at which it is thrown is 23 degrees, what is its initial velocity?


Homework Equations


5 kinematic equations:
a = (v2-v1)/t
d=0.5(v1+v2)t
d=v1t+0.5at^2
d=v2t-0.5at^2
v2^2=v1^2+2ad
Equation for uniform motion:
v=d/t


I have no idea how to solve this :cry: Any help is appreciated Thanks :smile:
 
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HelloImAsh said:

Homework Statement


An object that is thrown covers a distance of 8.59 m. If the angle at which it is thrown is 23 degrees, what is its initial velocity?


Homework Equations


5 kinematic equations:
a = (v2-v1)/t
d=0.5(v1+v2)t
d=v1t+0.5at^2
d=v2t-0.5at^2
v2^2=v1^2+2ad
Equation for uniform motion:
v=d/t


I have no idea how to solve this :cry: Any help is appreciated Thanks :smile:

Homework Statement


Homework Equations


The Attempt at a Solution

Horizontal motion is independent of vertical motion.
 
SammyS said:
Horizontal motion is independent of vertical motion.

What do you mean? :confused:
 
Firstly you can break it into its horizontal and vertical vectors, and you know in the horizontal direction there is no force acting on it therefore its speed will stay constant.

In the vertical direction you may find how long the ball stays in the air for.

In summary find how long the ball was in the air for.

calculate the initial horizontal speed using V=d/t you now have t and d
 

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