Finding the initial velocity of a vector

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HelloImAsh
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Homework Statement


An object that is thrown covers a distance of 8.59 m. If the angle at which it is thrown is 23 degrees, what is its initial velocity?


Homework Equations


5 kinematic equations:
a = (v2-v1)/t
d=0.5(v1+v2)t
d=v1t+0.5at^2
d=v2t-0.5at^2
v2^2=v1^2+2ad
Equation for uniform motion:
v=d/t


I have no idea how to solve this :cry: Any help is appreciated Thanks :smile:
 
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HelloImAsh said:

Homework Statement


An object that is thrown covers a distance of 8.59 m. If the angle at which it is thrown is 23 degrees, what is its initial velocity?


Homework Equations


5 kinematic equations:
a = (v2-v1)/t
d=0.5(v1+v2)t
d=v1t+0.5at^2
d=v2t-0.5at^2
v2^2=v1^2+2ad
Equation for uniform motion:
v=d/t


I have no idea how to solve this :cry: Any help is appreciated Thanks :smile:

Homework Statement


Homework Equations


The Attempt at a Solution

Horizontal motion is independent of vertical motion.
 
SammyS said:
Horizontal motion is independent of vertical motion.

What do you mean? :confused:
 
Firstly you can break it into its horizontal and vertical vectors, and you know in the horizontal direction there is no force acting on it therefore its speed will stay constant.

In the vertical direction you may find how long the ball stays in the air for.

In summary find how long the ball was in the air for.

calculate the initial horizontal speed using V=d/t you now have t and d