Finding the inverse laplace transform of (2/(s+2)^4) using Convolution theorem.

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theBEAST
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Homework Statement


Find the inverse laplace transform of (2/(s+2)^4) using the given table of identities:

Homework Equations


Here are the given identities:
Table of Laplace transform pairs with columns f(t) and F(s): unit impulse, step, ramp, exponential, t e^(-at), damped sine and cosine, derivatives, integral, convolution, and time shift.


The Attempt at a Solution


Alright, I realize that there is a simple identity that I can use with a factorial symbol, but this identity is not on our formula sheet, so I decided to try it with convolution theorem.

Handwritten working on lined paper: Y(s) = 2/(s+2)^4 rewritten as 2[1/(s+2)^2 * 1/(s+2)^2], then 2G(s)H(s), a convolution integral for y(t), a Wolfram result marked WRONG, and the stated correct answer (1/3)e^(-2t) t^3.


What did I do wrong and also is there an easier way given the table of identities? Thanks!
 
Where did you get that flawed table? Discard it.

[tex]G(s)H(s) \rightarrow \int_0^t g(t-\tau)h(\tau) \mathop{d\tau}[/tex]

Clearly both functions should depend on the integration variable.
 
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lurflurf said:
Where did you get that flawed table? Discard it.

[tex]G(s)H(s) \rightarrow \int_0^t g(t-\tau)h(\tau) d\tau[/tex]

Clearly both functions should depend on the integration variable.

Ahh, thanks!

This is the table that we get for our midterms and final lol

Is there an easier way to solve this with another identity? The integral is pretty messy.
 
That integral is not so bad, and you wanted to avoid using

[tex]\frac{1}{(s+a)^{n+1}} \rightarrow \frac{t^n}{n!} e^{-a \mathop{t}}[/tex]

you could derive it. It helps to have a longer table with fewer errors.
 
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