Finding the Limit of (1+x+x^2) as x Approaches 0

[helpme7]

closed.

 

[flatmaster]

Within a set of parentheses, you will have

1+x+x^2. The limit of this as x--> 0 is 1.

You then have

((1)^(1/x)-e)

One to any power is still one, so

1-e