Finding The Limit Of A 3D Function

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SUMMARY

The discussion focuses on finding the limit of the function (X²Y)/(X² + Y⁴) as both X and Y approach 0. Multiple approaches, including substituting paths like y = x and y = 0, yield a limit of zero. However, to rigorously prove this limit, the use of polar coordinates is recommended, where x is expressed as r*cos(θ) and y as r*sin(θ). This transformation simplifies the analysis of the limit as r approaches 0.

PREREQUISITES
  • Understanding of limits in multivariable calculus
  • Familiarity with polar coordinates transformation
  • Basic graphing techniques for functions of two variables
  • Knowledge of approaching limits along different paths
NEXT STEPS
  • Study the application of polar coordinates in limit evaluation
  • Learn about epsilon-delta definitions of limits in multivariable calculus
  • Explore the concept of continuity in functions of multiple variables
  • Investigate advanced limit techniques such as the squeeze theorem
USEFUL FOR

Students studying multivariable calculus, educators teaching limit concepts, and anyone interested in advanced mathematical analysis techniques.

Baumer8993
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Homework Statement


Find the limit as X, and Y both approach 0 of (X2Y)/(X2 + Y4)


Homework Equations


The equation from above.


The Attempt at a Solution


I have been doing the technique of approaching from different lines such as y = x, or x = y,
x = 0, and y = 0. All of them give me a limit of zero, so that will not do. I graphed the function online, and it appears as if the function does have a limit of zero. How would I prove this? I think I need to do something with polar coordinates, but I am not sure how to do that.
 
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EDIT:
I'd go with SammyS's
 
Baumer8993 said:

Homework Statement


Find the limit as X, and Y both approach 0 of (X2Y)/(X2 + Y4)

Homework Equations


The equation from above.

The Attempt at a Solution


I have been doing the technique of approaching from different lines such as y = x, or x = y,
x = 0, and y = 0. All of them give me a limit of zero, so that will not do. I graphed the function online, and it appears as if the function does have a limit of zero. How would I prove this? I think I need to do something with polar coordinates, but I am not sure how to do that.
Yes. Change to polar coordinates.

x=r\cos(\theta)

y=r\sin(\theta)
 
Last edited:

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