Finding the Limit of Curvature for a Polar Curve

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The discussion focuses on finding the curvature K of the polar curve r=e^(a*theta) and determining its limits as theta and a approach infinity. Participants initially attempted to convert the polar equations to Cartesian coordinates but found the process cumbersome. They then explored using properties of limits and faced challenges with the potential for division by zero in their calculations. Ultimately, a suggestion to use the polar coordinates' curvature formula led to a successful derivation, resulting in K approaching 0 for both limits. The conclusion confirms that the curvature approaches zero as both parameters tend to infinity.
WK95
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Homework Statement


Given the polar curve r=e^(a*theta), a>0, find the curvature K and determine the limit of K as (a) theta approaches infinity and (b) as a approaches infinity.

Homework Equations


x=r*cos(theta)
y=r*sin(theta)
K=|x'y''-y'x''|/[(x')^2 + (y')^2]^(3/2)

The Attempt at a Solution


I've tried converting the polar curve using the first equation, solving for their first and second derivatives, then plugging them into equation 3 but that gets very, very long.

So next, I apply the properties of limits to the relevant equations. However, I get stuck when I need to find the limit of asin(x), acos(x), sin(x), cos(x) as x approaches infinity. What now?
 
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You know sin(x) and cos(x) are limited. That should be sufficient.

If asin is the inverse sine, then asin(x) with x to infinity shouldn't occur. If it is a*sin(x), then see above.
 
I'm getting 0 for the limit of x', x'', y', y'' as a approaches infinity and when theta approaches infinity.
 
A curvature that approaches zero makes sense.
 
mfb said:
A curvature that approaches zero makes sense.

Yes, but then I'd end up with a 0 in the denominator in the third equation which wouldn't work. However, that would require me to find a work around and solve for the limit some other way so I don't get 0/0. I haven't been able to figure out what I have to do to get around that.

I am expecting the curvature to be 0 in both cases when a or theta approaches infinity so I'm expecting the numerator to be 0.
 
WK95 said:

Homework Statement


Given the polar curve r=e^(a*theta), a>0, find the curvature K and determine the limit of K as (a) theta approaches infinity and (b) as a approaches infinity.

Homework Equations


x=r*cos(theta)
y=r*sin(theta)
K=|x'y''-y'x''|/[(x')^2 + (y')^2]^(3/2)

The Attempt at a Solution


I've tried converting the polar curve using the first equation, solving for their first and second derivatives, then plugging them into equation 3 but that gets very, very long.

So next, I apply the properties of limits to the relevant equations. However, I get stuck when I need to find the limit of asin(x), acos(x), sin(x), cos(x) as x approaches infinity. What now?
Instead of using the radius of curvature formula for cartesian coordinates, why don't you try the equivalent formula for polar coordinates?

http://mathworld.wolfram.com/RadiusofCurvature.html
 
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SteamKing said:
Instead of using the radius of curvature formula for cartesian coordinates, why don't you try the equivalent formula for polar coordinates?

http://mathworld.wolfram.com/RadiusofCurvature.html
Thanks! That's just what I need.

I've ended up with R=sqrt((a^2 + 1)e^(2ax)) so K=1/sqrt((a^2 + 1)e^(2ax)). Taking the limit as a approaches infinity I get 0 and taking the limit as x approaches infinity, I also get 0.
 

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