Finding the Locus of a Moving Point: Solving for a Hyperbola Using Dot Products

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Homework Help Overview

The problem involves finding the locus of a moving point P based on its distances from four fixed points A, A', B, and B'. The relationship is given by the equation AP.PA' = BP.PB', which suggests a hyperbolic locus.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the interpretation of the equation, particularly the nature of the terms AP, PA', BP, and PB', questioning whether they represent vector quantities or scalar distances. There is also an examination of the calculations involving dot products and the need for clarity in the steps taken.

Discussion Status

Some participants have identified potential errors in the calculations and suggested re-evaluating the interpretation of the terms involved. There is a productive exchange of ideas regarding the mathematical approach, with one participant proposing an alternative interpretation that could lead to a clearer understanding of the problem.

Contextual Notes

There is a noted ambiguity in the problem statement regarding the use of dot products versus scalar multiplication, which has led to confusion in the calculations. Participants are encouraged to clarify these definitions as part of their exploration.

Appleton
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Homework Statement



A point P moves so that its distances from A(a, 0), A'(-a, 0), B(b, 0) B'(-b, 0) are related by the equation AP.PA'=BP.PB'. Show that the locus of P is a hyperbola and find the equations of its asymptotes.

Homework Equations

The Attempt at a Solution



AP.PA' = ((a-x)\boldsymbol i + y\boldsymbol j).((-a-x)\boldsymbol i+y\boldsymbol j)
AP.PA' = x^2-a^2+y^2
BP.PB' = ((b-x)\boldsymbol i + y\boldsymbol j).((-b-x)\boldsymbol i+y\boldsymbol j)
BP.PB'= x^2-b^2+y^2

So

a^2=b^2

This result sugests that their is no constraint on P. This is not consistent with the question.
 
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Appleton said:
AP.PA' = ((a-x)\boldsymbol i + y\boldsymbol j).((-a-x)\boldsymbol i+y\boldsymbol j)
AP.PA' = x^2-a^2+y^2
BP.PB' = ((b-x)\boldsymbol i + y\boldsymbol j).((-b-x)\boldsymbol i+y\boldsymbol j)
BP.PB'= x^2-b^2+y^2
The second line does not follow from the first line and the fourth does not follow from the third.
Write out the intermediate steps between the first and second lines and you will see what went wrong.
 
Thanks for your reply andrewkirk. Unfortunately I'm still not able to identify my error. Here are the steps I omitted:

AP.PA' = ((a-x)\boldsymbol i + y\boldsymbol j).((-a-x)\boldsymbol i+y\boldsymbol j)

The dot product is distributive over vector addition, so

AP.PA' = (a-x)\boldsymbol i.(-a-x)\boldsymbol i+ y\boldsymbol j.(-a-x)\boldsymbol i+(a-x)\boldsymbol i.y\boldsymbol j+y\boldsymbol j.y\boldsymbol j

\boldsymbol i.\boldsymbol i=\boldsymbol j.\boldsymbol j=1 and \boldsymbol i.\boldsymbol j= 0

so
AP.PA' = x^2-a^2+y^2

Alternatively this shorthand is suggested by my book;

if
\boldsymbol a = x_1\boldsymbol i+ y_1\boldsymbol j

and
\boldsymbol b = x_2\boldsymbol i+ y_2\boldsymbol j

then
\boldsymbol a.\boldsymbol b=x_1x_2+y_1y_2

so
((a-x)\boldsymbol i + y\boldsymbol j).((-a-x)\boldsymbol i+y\boldsymbol j) =(a-x)(-a-x)+y^2

= -a^2+x^2+y^2
 
Actually you're quite correct. My mistake. I can't see any error in your calculations.

However, I have another idea. The question refers to the distances of P from the four points, not to the displacement vectors. If they are being careful with their words then the items AP, PA', BP, PB' are to be interpreted as scalar amounts, not vectors, and the dot between them is to be interpreted as simple multiplication (not a dot product).

I suggest trying what happens when you make that interpretation.
 
Thanks for that, it makes sense now, so the asymptotes must be y =+-x
 

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