Finding the magnetic field inside a material shell under external field

[DaniV]

Homework Statement

A uniform external field B_{ext} = B_{ext}xˆ is applied to an infinitely long cylindrical shell with inside radius a, outside radius b, and relative permeability κ = µ/µ_{0}. The rest of space is vacuum. Show that the field inside the shell is screened to the value :
Bin = 4κb^{2}Bext /((κ + 1)^{2}b^{2} − (κ − 1)^{2}a^{2})

Relevant Equations

B=µ*H,
B=µ_{0}(H+M) when M is the magnetisation of the material

I know that we need to use some boundry condition both on the a radius surface and the b radius surface and somehowuse the superposition on them both, the boundry condition most be for the tangential and the radial part,
the only things I got is that i don`t know how to produce a magnetisation M from the magnetic material, and how tofind some H_{in} that is suitable
to the problem?

the only relations that I suceed to produce it`s:
µ_{0}*κ*H_{in}*r(hat)=B_{ext}sin(θ)
µ_{0}*κ*H_{in}*θ(hat)=B_{ext}cos(θ)

 

[timetraveller123]

i am not sure if the provided answer is correct . i worked out a different answer and it matches with answer i see over the internet
for example in wikipedia,
https://en.wikipedia.org/wiki/Electromagnetic_shieldingi am getting this also

(from wikipedia)

 

[TSny]

i worked out a different answer and it matches with answer i see over the internet
for example in wikipedia,
https://en.wikipedia.org/wiki/Electromagnetic_shielding

The Wikipedia result is for a spherical shell, not a cylindrical shell.

 

[timetraveller123]

oh oops my bad didn't read cylindrical

edit:
sorry for the inconvenience caused yes the answer is correct
i worked it out again the method is almost exactly same as the spherical one

 

[TSny]

oh oops my bad didn't read cylindrical

That's OK. I do that sort of thing all the time.