Finding the Magnitude and Placement of Force F for a Loading System

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The discussion focuses on determining the magnitude and direction of force F, along with its placement on a beam, to achieve a resultant force of 12 kN downward at point A and a clockwise couple moment of 50 kN*m. Participants are working through equations for the horizontal and vertical components of force, as well as the moment equation. Key equations include Fx = Fcos(theta) - 1.4 and Fy = Fsin(theta) + 7.8, with the resultant force being calculated using the square root of the sum of the squares of these components. The importance of carefully reading the problem statement is emphasized, as it clarifies the relationships between the forces and moments involved. Overall, the discussion highlights the analytical approach required to solve the loading system problem effectively.
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Homework Statement



Determine the magnitude and direction (theta) of force F and its placementd on the beam so that the loading system is equivalent to a resultant forece of 12kN acting vertically downward at point A and a clockwise coupuple moment of 50kN*m

Homework Equations


M=Fd


The Attempt at a Solution

I am writing equations for resultant Fx and Fy and also for the moment. Fx=Fcos(theta)-1.4 Fy=Fsin(theta)+7.8 then squaring them and putting under the square root to equal 12.For the moment I am getting 14.6=Fsin(theta)*x. x is (7-d).
 

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bigu01 said:
squaring them and putting under the square root to equal 12.
It says a resultant of 12 downwards.
 
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Ohh, then Fcos(theta)=1.4, now makes sense, thanks a lot.Once again it is shown to me that reading the question REALLY carefully is really important :(.
 
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