Statics Questions involving finding forces

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SUMMARY

The discussion focuses on solving statics problems involving forces, specifically in the context of a free body diagram (FBD) for a roller system. Key equations utilized include Fx = Fcos(theta) and Fy = Fsin(theta) to resolve forces into their components. Participants express difficulty in visualizing forces acting on the roller and the spring, particularly the vertical force derived from the spring constant and distance. The conversation emphasizes the importance of understanding contact forces and their directions in static equilibrium scenarios.

PREREQUISITES
  • Understanding of static equilibrium principles
  • Familiarity with free body diagrams (FBD)
  • Knowledge of trigonometric functions in physics
  • Basic concepts of force resolution (Fx and Fy)
NEXT STEPS
  • Study advanced free body diagram techniques for complex systems
  • Learn about static equilibrium conditions in multi-body systems
  • Explore the application of Hooke's Law in static scenarios
  • Investigate the role of contact forces in mechanical systems
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Students studying physics, particularly those focusing on statics and mechanics, as well as educators looking for insights into teaching force resolution and free body diagrams.

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Homework Statement



http://ft.trillian.im/b0f9eae6eee2cb82091d0bd460ed09948b0cf819/6bh6EcByYLCp8YJWVJ5pqqnrqKcIY.jpg

Homework Equations



Fx= Fcos(theta)
Fy=Fsin(theta)



The Attempt at a Solution



Starting with number one, I can't understand how to find the force given by that contact by B. The vertical force on the spring can be found by the given constant and distance of course.

I can't even see the forces on the other 2. So hard to visualize a FBD >.<
 
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Hi Kalookakoo! :smile:
Kalookakoo said:
Starting with number one, I can't understand how to find the force given by that contact by B.

The force between the roller and that thing at the bottom must be perpendicular to the surface (so through the centre, B, of the roller) …

so, doing a free body diagram for the roller on its own, the direction of the force at B must be … ? :wink:
 

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