Finding the magnitude of an electric field.

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SUMMARY

The discussion focuses on calculating the magnitude of the electric field at a point midway between a -8.1μC charge and an 8.9μC charge, which are 8.0 cm apart. The correct formula used is E = k/r²(Q1 + Q2), where k is Coulomb's constant. The user initially calculated the electric field as 2.4e7 N/C but realized the distance r should be 0.04 m, not 0.08 m, leading to an incorrect result. The direction of the electric field is towards the negative charge due to its negative polarity.

PREREQUISITES
  • Understanding of Coulomb's Law and electric fields
  • Familiarity with the concept of charge polarity
  • Basic knowledge of significant figures in scientific calculations
  • Ability to perform unit conversions (e.g., cm to m)
NEXT STEPS
  • Review the principles of electric field calculations using Coulomb's Law
  • Practice problems involving multiple point charges and their electric fields
  • Learn about the superposition principle in electric fields
  • Explore the concept of electric field lines and their representation
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Students studying electromagnetism, physics educators, and anyone preparing for exams involving electric fields and charge interactions.

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Homework Statement


Determine the magnitude of the electric field at a point midway between a -8.1μC and a 8.9μC charge 8.0cm apart. Assume no other charges are nearby.
Determine the direction.
(Answer in two sig figs.)

Homework Equations


E=k/r^2(Q1+Q2)

The Attempt at a Solution



I drew this: -8.1---------p----------8.9

This is what I think I'm supposed to do.

The field due to -8.1 charge points toward it.
The field due to 8.9 points away. So they are both pointing towards the negative charge?

so E=k/.08^2(8.1e-6+8.9e-6)=2.4e7 N/C but this is incorrect. Please explain why! Thanks.
 
Last edited:
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I want to slap myself now...is it because r=.04m? Want assurance because I'm on my last strike.
 

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