jr4life said:no they didnt give the mass of the block, that is why I am so confused my teacher said something about sigma Fx=0 and sigma Fy=0 but i don't know what to do with those numbers, all i know is velocity is constant which makes acceleration 0 which makes force of x and y 0, but after that I am lost
jr4life said:In the x direction is the pushing force and force of friction and in the y direction is force of gravity on a box whos mass is not given and the normal force, i think the lack of given numbers is confuing me
jr4life said:in x direction it would be (mass)(0) so resultant force would be 0, because acceleration would be 0 due to constant velocity and in y direction (mass)(9.8) and then i don't really know what you could do with that...
learningphysics said:Write the equations using Fpushing, friction, mg, Fnormal... how do they add or subtract?
jr4life said:mg-Fnormal=0
this is where i get confused with x because they are not in equilibrium so they wouldn't equal 0
Fpushing-friction=?? idk
learningphysics said:It equals 0, because acceleration is 0 (constant velocity). Now, you also know that friction = [tex]\mu * F_{normal}[/tex]
Solve for Fpushing using your two equations, in terms of mass, [tex]\mu[/tex] and g.
jr4life said:ok, i understand why it equals zero now but when you use that equation would it be
friction=(0.5)(9.8m) and which two equations are you referring to?
learningphysics said:Yes, that's right...
The two equations I meant were:
Fpushing - friction = 0
Fnormal - mg = 0
you actually used the second equation to get friction = 0.5*9.8*m
So what does Fpushing come out to...
jr4life said:Fpushing-(0.5)(9.8m)=0
Fpushing-4.9m=0
Fpushing=4.9m??
FedEx said:Seems good to me.