An 8kg ball moves down a 12m high inclined plane with a speed of 6m/s. By the time it reaches the bottom, the speed is measured to be 12m/s. What is the frictional force opposing the motion? The inclined plane has an angle of 30 degrees with respect to the ground.
Potential energy = mgh
Kinetic energy = 1/2mv^2
Work done by external forces = ΔE
Work done: Fs (or Fscos(theta))
The Attempt at a Solution
The first step is to calculate the potential energy and kinetic energy, which is 960J and 576J respectively. Hence ΔE=960-576=384J.
Now, since the height is 12m and the angle is 30 degrees, the length of the inclined plane is 12/sin30 or 24m.
Finally, 24f=384 which yields an answer for f as 16N.
I might have gotten the correct answer, but in the book it says that the answer is supposed to be 22N, so I'm assuming I'm missing something, perhaps it has something to do with the initial speed which I haven't included in my calculations.
Thanks in advance,