Finding the Major Axis Angle of an Ellipse Given Rotated Equations

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    Ellipse Geometry
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The discussion focuses on proving that the equations x=acos(θ) and y=bcos(θ + δ) represent an ellipse and determining the angle of its major axis relative to the x-axis. A rotation matrix is applied to the standard ellipse equations, leading to a new form that incorporates the angle ψ. The relationship between the angles ψ and δ is explored to express the rotated ellipse in standard form. The method involves eliminating θ using the cosine relationship, ultimately confirming the elliptical nature of the equations. The solution demonstrates the connection between the angles and successfully derives the standard form of the ellipse.
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Homework Statement



Prove that the equations x=acos(\theta) and y=bcos(\theta +\delta ) is the equation of an ellipse and what angle does this ellipse's major axis make with the x axis?

Homework Equations



Equation of an ellipse is x=acos\theta, y=asin\theta
Rotation matrix is for a rotation by \psi is A=\begin{pmatrix} cos\psi & -sin\psi \\ sin\psi & cos\psi \end{pmatrix}

The Attempt at a Solution



I know the special case of \delta = \pi/2 is easy but I cannot do it for arbitrary \delta. I worked out what an ellipse whose major axis forms an angle \psi with the x-axis looks like. I did this by applying a rotation matrix to the standard equation x=acos\theta, y=bsin\theta

This gives x= acos\theta cos\psi - bsin\theta sin\psi and y= acos\theta sin\psi + bsin\theta cos\psi

Now, what is the relation between \psi and \delta in general. And I need to show that the equations x=acos(\theta) and y=bcos(\theta +\delta ) can be brought to the same form as x= acos\theta cos\psi - bsin\theta sin\psi and y= acos\theta sin\psi + bsin\theta cos\psi
 
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This might not be the most efficient method. Use
$$\cos \theta = \frac{x}{a}$$ to eliminate ##\theta## from
$$\frac{y}{b} = \cos(\theta+\delta) = \cos \theta \cos \delta - \sin\theta \sin \delta$$ to get the equation of an ellipse in standard form.
 
Thanks Vela. It took some doing but it worked!
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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