Finding the Major Axis Angle of an Ellipse Given Rotated Equations

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    Ellipse Geometry
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SUMMARY

The discussion focuses on proving that the equations x=acos(θ) and y=bsin(θ + δ) represent an ellipse and determining the angle of the major axis with respect to the x-axis. The participant successfully applied a rotation matrix to the standard ellipse equation, transforming it into the required form. The relationship between the angle ψ (major axis) and δ (rotation) was established through the use of trigonometric identities. The final solution involved eliminating θ using the cosine function to derive the standard form of the ellipse equation.

PREREQUISITES
  • Understanding of ellipse equations and their standard forms
  • Familiarity with rotation matrices and their applications
  • Knowledge of trigonometric identities and their manipulation
  • Basic skills in algebraic manipulation and solving equations
NEXT STEPS
  • Study the derivation of the ellipse equation from parametric equations
  • Learn about the properties of rotation matrices in 2D geometry
  • Explore the application of trigonometric identities in transforming equations
  • Investigate the relationship between angles in rotated coordinate systems
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Students in mathematics, particularly those studying geometry and algebra, as well as educators looking to enhance their understanding of ellipse properties and transformations.

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Homework Statement



Prove that the equations x=acos(\theta) and y=bcos(\theta +\delta ) is the equation of an ellipse and what angle does this ellipse's major axis make with the x axis?

Homework Equations



Equation of an ellipse is x=acos\theta, y=asin\theta
Rotation matrix is for a rotation by \psi is A=\begin{pmatrix} cos\psi & -sin\psi \\ sin\psi & cos\psi \end{pmatrix}

The Attempt at a Solution



I know the special case of \delta = \pi/2 is easy but I cannot do it for arbitrary \delta. I worked out what an ellipse whose major axis forms an angle \psi with the x-axis looks like. I did this by applying a rotation matrix to the standard equation x=acos\theta, y=bsin\theta

This gives x= acos\theta cos\psi - bsin\theta sin\psi and y= acos\theta sin\psi + bsin\theta cos\psi

Now, what is the relation between \psi and \delta in general. And I need to show that the equations x=acos(\theta) and y=bcos(\theta +\delta ) can be brought to the same form as x= acos\theta cos\psi - bsin\theta sin\psi and y= acos\theta sin\psi + bsin\theta cos\psi
 
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This might not be the most efficient method. Use
$$\cos \theta = \frac{x}{a}$$ to eliminate ##\theta## from
$$\frac{y}{b} = \cos(\theta+\delta) = \cos \theta \cos \delta - \sin\theta \sin \delta$$ to get the equation of an ellipse in standard form.
 
Thanks Vela. It took some doing but it worked!
 

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