Finding the maximum compression of the spring

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SUMMARY

The discussion centers on the calculation of maximum compression in a spring related to a mass's vertical drop. The correct vertical drop value is confirmed to be 0.8 meters, which is essential for accurate calculations. A misunderstanding arose due to the omission of the object's height in the problem statement. Participants emphasized the importance of verifying the problem details with the lecturer to resolve discrepancies in numerical answers.

PREREQUISITES
  • Understanding of spring mechanics and Hooke's Law
  • Knowledge of gravitational potential energy calculations
  • Familiarity with basic algebra for solving equations
  • Ability to interpret physics problem statements accurately
NEXT STEPS
  • Review Hooke's Law and its applications in spring compression
  • Study gravitational potential energy and its relation to spring systems
  • Practice solving physics problems involving vertical drops and spring mechanics
  • Consult resources on effective communication with educators regarding problem-solving
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone involved in mechanics, particularly those studying spring dynamics and energy conservation principles.

Sean Harold
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Homework Statement
11. Figure 7 shows a 3 kg box starts to move down an inclined plane with initial speed of 5 ms. It travels along the smooth surface and finally compresses the spring which has the spring constant of 400 Nm. Determine the maximum compression of the spring. [Given gravitational acceleration, g = 9.81 ms ²]

Correction:
Theta is not given and the height of the box from the ground is 0.8m
Relevant Equations
By using the conservation of energy,
The initial of total energy=The final of total energy
∑Eᵢ=∑Eғ
Kᵢ+Uᵢ=Kғ+Uғ
mghᵢ+1/2mvᵢ²=mghғ+1/2kx²
(3)(9.81)(0.8)+1/2(3)(5)²=(3)(9.81)(0)+1/2(400)(x)²
61.044=200x²
61.044/200=x²
x²=0.30522
x=0.5525m
Here is the answer I got for the question.
16319724068101635167086205417130.jpg
 
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Where did the correction come from? It is not part of the statement of the problem that you posted. Your solution would be correct if the overall vertical drop of the mass were 0.8 m. However, the answer you got does not match the given answer so something is amiss.
 
kuruman said:
Where did the correction come from? It is not part of the statement of the problem that you posted. Your solution would be correct if the overall vertical drop of the mass were 0.8 m. However, the answer you got does not match the given answer so something is amiss.
My lecturer told me that she had forgotten to put the height of the object in the question.
 
Sean Harold said:
My lecturer told me that she had forgotten to put the height of the object in the question.
In that case, I think you should show your solution to your lecturer and ask her why your numerical answer does not match the given answer. Your method is correct and that's what counts.
 
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kuruman said:
In that case, I think you should show your solution to your lecturer and ask her why your numerical answer does not match the given answer. Your method is correct and that's what counts.
Alright thanks for the help.
 

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