Finding the maximum compression of the spring

AI Thread Summary
The discussion revolves around a discrepancy in the solution to a spring compression problem due to missing information about the object's height. The lecturer acknowledged the omission, indicating that the overall vertical drop should have been 0.8 m for the solution to align with the provided answer. Participants suggest that the correct method was used, and the focus should be on clarifying the issue with the lecturer. The importance of verifying the problem statement and ensuring all necessary details are included is emphasized. Overall, the conversation highlights the need for clear communication in problem-solving scenarios.
Sean Harold
Messages
3
Reaction score
2
Homework Statement
11. Figure 7 shows a 3 kg box starts to move down an inclined plane with initial speed of 5 ms. It travels along the smooth surface and finally compresses the spring which has the spring constant of 400 Nm. Determine the maximum compression of the spring. [Given gravitational acceleration, g = 9.81 ms ²]

Correction:
Theta is not given and the height of the box from the ground is 0.8m
Relevant Equations
By using the conservation of energy,
The initial of total energy=The final of total energy
∑Eᵢ=∑Eғ
Kᵢ+Uᵢ=Kғ+Uғ
mghᵢ+1/2mvᵢ²=mghғ+1/2kx²
(3)(9.81)(0.8)+1/2(3)(5)²=(3)(9.81)(0)+1/2(400)(x)²
61.044=200x²
61.044/200=x²
x²=0.30522
x=0.5525m
Here is the answer I got for the question.
16319724068101635167086205417130.jpg
 
Physics news on Phys.org
Where did the correction come from? It is not part of the statement of the problem that you posted. Your solution would be correct if the overall vertical drop of the mass were 0.8 m. However, the answer you got does not match the given answer so something is amiss.
 
kuruman said:
Where did the correction come from? It is not part of the statement of the problem that you posted. Your solution would be correct if the overall vertical drop of the mass were 0.8 m. However, the answer you got does not match the given answer so something is amiss.
My lecturer told me that she had forgotten to put the height of the object in the question.
 
Sean Harold said:
My lecturer told me that she had forgotten to put the height of the object in the question.
In that case, I think you should show your solution to your lecturer and ask her why your numerical answer does not match the given answer. Your method is correct and that's what counts.
 
  • Like
Likes Sean Harold
kuruman said:
In that case, I think you should show your solution to your lecturer and ask her why your numerical answer does not match the given answer. Your method is correct and that's what counts.
Alright thanks for the help.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top