Finding the minimal polynomial of an irrational over Q

Click For Summary
SUMMARY

The minimal polynomial of the expression \( a = \sqrt{1 + \sqrt{3}} \) over \( \mathbb{Q} \) is derived by identifying its four conjugates: \( a = \sqrt{1 + \sqrt{3}} \), \( b = \sqrt{1 - \sqrt{3}} \), \( c = -\sqrt{1 - \sqrt{3}} \), and \( d = -\sqrt{1 + \sqrt{3}} \). The degree of the extension \( [\mathbb{Q}(a):\mathbb{Q}] \) is confirmed to be 4, indicating that the minimal polynomial will be a quartic polynomial formed by the product \( (x-a)(x-b)(x-c)(x-d) \). An alternative method involves isolating the square root of 3, leading to the conclusion that \( f(a) - 3 \) can represent the minimal polynomial if \( f(a) \) is expressed in terms of \( a \).

PREREQUISITES
  • Understanding of minimal polynomials in field extensions
  • Familiarity with conjugates in algebraic expressions
  • Knowledge of square roots and their properties
  • Basic concepts of field theory and algebraic numbers
NEXT STEPS
  • Study the derivation of minimal polynomials for algebraic numbers
  • Learn about field extensions and their degrees, particularly in relation to \( \mathbb{Q} \)
  • Explore the properties of conjugates in algebraic expressions
  • Investigate the implications of isolating terms in polynomial equations
USEFUL FOR

Mathematics students, particularly those studying abstract algebra, field theory, or anyone interested in the properties of algebraic numbers and minimal polynomials.

PsychonautQQ
Messages
781
Reaction score
10

Homework Statement


Let a = (1+(3)^1/2)^1/2. Find the minimal polynomial of a over Q.

Homework Equations

The Attempt at a Solution


Maybe the first thing to realize is that Q(a):Q is probably going to be 4, in order to get rid of both of the square roots in the expression. I also suspect that +/-(3)^1/2 will be roots of the minimal polynomial, as Q(a):Q = [Q(a):Q((3)^1/2)]*[Q(3^1/2):Q]. I do not know where to go from here, any advice PF?
 
Physics news on Phys.org
$$a=\sqrt{1+\sqrt{3}}$$
so your on the right track looking for 4 conjugates
consider all sign variations of square roots
$$\pm\sqrt{1\pm\sqrt{3}}$$
the minimum polynomial will be
(x-a)(x-b)(x-c)(x-d)
where a,b,c,d are the four conjugates
$$a=\sqrt{1+\sqrt{3}}\\
b=\sqrt{1-\sqrt{3}}\\
c=-\sqrt{1-\sqrt{3}}\\
d=-\sqrt{1+\sqrt{3}}\\$$
another possibly easier approach is to isolate 3 in your equation for a
the minimal polynomial of 3 is
x-3
so
f(a)-3
is the minimal polynomial of a if f(a) is 3 in terms of a
 
  • Like
Likes   Reactions: PsychonautQQ

Similar threads

  • · Replies 28 ·
Replies
28
Views
5K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 18 ·
Replies
18
Views
6K
  • · Replies 27 ·
Replies
27
Views
7K
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
4
Views
2K
Replies
13
Views
2K
  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K