- #1
PsychonautQQ
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Homework Statement
Describe the structure of the Galois group for G(Q(c):Q) where c is a 14th primitive root of unity
Homework Equations
The Attempt at a Solution
the minimal polynomial for c over Q is f(x)=x^6-x^5+x^4-x^3+x^2-x+1. Is the galois group isomorphic to Z*_14? Or maybe that's only true for prime numbers?
Anyway, c has order 6, so c^1,...,c^6=1 will all be roots of it's minimal polynomial f(x). The galois group will have a map b(1)=c^i for each 0>i>6. A part of me wants to say the galois group is the cyclic group of order 6, but the alternating polynomial makes me think it's a bit trickier than that. Could the galois group be some sort of alternating cyclic group? If that makes any sense...
Thanks PF!