Finding the minimas from EM radiation.

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Homework Help Overview

The problem involves two coherent point sources of electromagnetic radiation, S1 and S2, separated by a distance of 4.0 m, emitting waves of 1.0 m wavelength. The task is to determine the positions of the first three maxima along a specified axis and to discuss the intensity at the nearest minimum.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the conditions for constructive interference and the differences between this scenario and single-slit diffraction. Some question the original poster's reasoning regarding the calculation of maxima positions and the nature of intensity at minima.

Discussion Status

The discussion is ongoing, with participants exploring the conditions for constructive interference and questioning assumptions about phase relationships between the two sources. Some guidance has been offered regarding the path difference and its relation to interference patterns.

Contextual Notes

There is a mention of potential confusion regarding the phase relationship of the waves and the implications for interference, as well as the need for clarity on the conditions for maxima and minima in this context.

sg001
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Homework Statement



6. S1 and S2 in the diagram are effective
point sources of radiation, excited by
the same oscillator. They are coherent
and in phase with each other. Placed 4.0 y m apart, they emit equal amounts of
power in the form of 1.0 m wavelength electromagnetic waves.
(a) Find the positions of the first (that is, the nearest), the second, and the third maxima of the received signal, as the detector is moved out along axis OX.
(b) Is the intensity at the nearest minimum equal to zero? Justify your answer.
[Ans: (a) 7/6m, 3m, 7.5m; (b) No]


the diagram looks like this


^y
|
|
|
|*S2
|
|
|
|
|
O*S1______________________>X
where d is the distance between S1 and S2


Homework Equations





The Attempt at a Solution



(a)
let dx = the distance along the x-axis to the respective minima.

so sin θ = d/√(dx2+d2)

for maxima's

dsinθ=mλ

for m=0 (the first maxima)

dsinθ = 0

so x =1 -d2

x =√15 m

but this is wrong but I'm not sure where I have gone wrong.. it should be 7/6 m

for m=0.
 
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This is not the same situation as with a slit, interference of the diffracted waves.

You have two different waves from different sources.
What is the condition of constructive interference when two waves meet? ehild
 
ehild said:
This is not the same situation as with a slit, interference of the diffracted waves.

You have two different waves from different sources.
What is the condition of constructive interference when two waves meet?


ehild

ok so use 2nt = mλ
 
that they are in phase...

so x=mλ
 
What is your reasoning behind your answer for (b) No?
 
Last edited:
sg001 said:
that they are in phase...

so x=mλ

Yes, a single wave has minima and maxima, but we speak about constructive interference of two waves. You said that the waves must be in phase. That is not quite true. The phase difference between them has to be integer multiple of 2pi. That corresponds an optical path difference nt=kλ, where n is the refractive index of the medium, t is the path difference, and k is an integer.
Supposing we have constructive interference on the x-axis at a point x. What is the path difference between the rays from the two sources when they reach x?

ehild
 

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