1. The problem statement, all variables and given/known data The Earth is surrounded by an electric field, pointing inward at every point. Assume a magnitude of E = 142N/C near the surface. a) What is the net charge on the Earth? b) How many excess electrons per square meter on the Earth's surface does this correspond to? E = 142 N/C Radius of Earth = 6.3781 km = 6,378,100 m 2. Relevant equations Gauss's Law = EA 3. The attempt at a solution So i know that i have to use Gauss's Law here. Which is simple the Electric Field, (given) and the area of the earth which is found be 4πr2 Gauss's Law = EA = (142) * (4πr2) = (142) * (4π(6,378,100)2) = (142) * (5.11e+14) = 7.26e+16 C however. After attempting that, i found it wasn't the right answer. Where did i go wrong? i haven't attempted the second part since i need to know the first part. But i assume that to do it i would have to find the surface area of the earth and divide it by the number i found in part a, then divide that by 1.6e-19 to find the number of electrons?