Finding the Net Direction and Speed of a Boat

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Homework Help Overview

The problem involves determining the net direction and speed of a boat affected by a stream and wind. The stream flows at 3 mph at an angle of 40 degrees north of east, while the wind blows at 11 mph from a direction of 50 degrees northwest.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss representing the velocities in an x-y coordinate system to facilitate vector addition. There is mention of converting back to polar coordinates after summing the components.
  • Some participants express confusion about the vector representation and seek clarification on how to properly illustrate the direction and components of the vectors involved.
  • There are attempts to calculate the x and y components of the boat's drift and the wind, with varying degrees of success and understanding.
  • Some participants suggest using trigonometric laws to solve the problem, while others question the angles involved in the triangle formed by the vectors.

Discussion Status

The discussion is ongoing, with participants exploring different methods to approach the problem. Some have provided guidance on using vector components, while others are still seeking clarification on the concepts involved. There is no explicit consensus on a single method or solution yet.

Contextual Notes

Participants note the complexity of the problem and the need for clear vector representation. There are indications of confusion regarding the angles and the application of trigonometric functions, which may affect the overall understanding of the problem.

964js7
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Homework Statement



a boat is a drift in a stream that flows at 3 mph 40* north of east. A wind blowing at 11 mph from a direction 50*NW also moves the boat. What will be the net direction and speed of the boat?

Homework Equations



Vwa = 3mph 40* NE
Vwi = 11mph 50* NW

The Attempt at a Solution



sin50* = X/3

Net direction will be 50* NE. Net speed will be 2.3 MPH.

It doesn't seem right, any help?
 
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Write the velocity vectors in an x-y coordinate system, say EW being x and NS being y. In xy coordinates it's easy to add them. Once you've done that, change back to the polar (magnitude-angle) representation.
 
Dick said:
Write the velocity vectors in an x-y coordinate system, say EW being x and NS being y. In xy coordinates it's easy to add them. Once you've done that, change back to the polar (magnitude-angle) representation.

Please explain that.. I am clueless on this matter
 
Last edited:
Take the x-components of the wind and the boat speed and add them together. Then take the y-components of each and add them together. The resulting components will be your final direction vector of the boat.

For example, the x-component of the boats drift it's speed*cos(theta). It's y-component will be it's speed*sin(theta).

Once you get the direction vector, take it's magnitude, and that will be the final speed of the boat.

Edit: if you need the angle of it's final direction with respect to the NSEW coordinate system, use trig and the x,y components of the final direction vector.
 
964js7 said:
Please explain that.. I am clueless on this matter

Bext I could do

http://img221.imageshack.us/img221/280/56727490pt5.jpg
http://g.imageshack.us/img221/56727490pt5.jpg/1/

You should also put arrows on the vectors to show what direction they are pointing. If '50*NW' means 50 degrees north of west, and if the wind is coming FROM that direction I would put the arrow on the bottom vertex. I think for the first vector the arrow should be on the upper vertex. Does that sound right? I'm trying to get the arrows to show which direction each will push the boat.

If so take each vector and write the vertical and horizontal component of each. For the first on I get x component +3*cos(40) and y component is +3*sin(40). What do you get for the second one? Once you've done that just add x and y components to get the total vector.
 
Last edited by a moderator:
Dick said:
You should also put arrows on the vectors to show what direction they are pointing. If '50*NW' means 50 degrees north of west, and if the wind is coming FROM that direction I would put the arrow on the bottom vertex. I think for the first vector the arrow should be on the upper vertex. Does that sound right? I'm trying to get the arrows to show which direction each will push the boat.

If so take each vector and write the vertical and horizontal component of each. For the first on I get x component +3*cos(40) and y component is +3*sin(40). What do you get for the second one? Once you've done that just add x and y components to get the total vector.

We were doing sample problems similar to this in class, and he said all we had to do was this:

http://img232.imageshack.us/img232/7516/78692884fy5.jpg

for these kind of problems.


I will attempt to make a new grid...
 
Last edited by a moderator:
Could someone make an example grid, so I know what to follow?
 
There's methodical way to solve it by x and y components but if you want to solve it using trig on the whole triangle, then you just figure out enough angles and sides to use law of sines or law of cosines etc. Your best bet is to start with the upper angle, isn't it 110 degrees?
 
Dick said:
There's methodical way to solve it by x and y components but if you want to solve it using trig on the whole triangle, then you just figure out enough angles and sides to use law of sines or law of cosines etc. Your best bet is to start with the upper angle, isn't it 110 degrees?

Can I do arithmetic or what? I meant 180-(50+40)=90. Not 110. This makes the problem particularly easy. Instead of those trig laws you can just use the definition of sin, cos, etc.
 

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