Finding the Null Space of a Matrix to Solving for the Solution Set

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Homework Help Overview

The discussion revolves around finding the null space of a given matrix. The matrix in question is a 3x5 matrix, and participants are exploring the implications of its reduced row echelon form (rref) in relation to the null space.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants describe their attempts to reduce the matrix to rref and express variables in terms of free variables. Questions arise regarding the interpretation of the null space and how to identify vectors that belong to it.

Discussion Status

Some participants have provided guidance on understanding the null space and its relationship to the original system of equations. There is an ongoing exploration of how to express the null space in terms of linear combinations of independent vectors.

Contextual Notes

There is mention of an extra column in the rref that may not be necessary, and participants are working under the constraints of the homework problem, which requires a clear understanding of the null space concept.

kkingkong
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Homework Statement



What is the null space of this matrices.
|1 1 0 3 1|
|0 1 -1 0 1|
|1 1 3 0 1|


The Attempt at a Solution


I reduced it to rref using agumented matrice(each one equals to zero )
|1 0 0 4 0 0|
|0 1 0 -1 1 0|
|0 0 1 -1 0 0|

and i get get x1=-x4 , x2= x4 + -x5, x3 = x4
but then what is the null space??
 
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kkingkong said:

Homework Statement



What is the null space of this matrices.
|1 1 0 3 1|
|0 1 -1 0 1|
|1 1 3 0 1|


The Attempt at a Solution


I reduced it to rref using agumented matrice(each one equals to zero )
|1 0 0 4 0 0|
|0 1 0 -1 1 0|
|0 0 1 -1 0 0|

and i get get x1=-x4 , x2= x4 + -x5, x3 = x4
but then what is the null space??
Your work so far is OK, but you just need to take it a little further.

Your final matrix, which BTW has an extra column (6th) that isn't needed, represents this system:
Code:
x[SUB]1[/SUB] = -x[SUB]4[/SUB]
x[SUB]2[/SUB] =  x[SUB]4[/SUB] - x[SUB]5[/SUB]
x[SUB]3[/SUB] =  x[SUB]4[/SUB]
x[SUB]4[/SUB] =  x[SUB]4[/SUB]
x[SUB]5[/SUB] =       x[SUB]5[/SUB]
If you sort of squint your eyes at what I wrote, you might be able to see that every vector x in the nullspace can be written as a linear combination of two vectors that are linearly independent.
 
Remember that the nullspace is the set of all vectors that would send your original system to the zero vector.

If you could find a set of vectors that are independent and send your system to the zero vector, then it seems as though the span of those vectors would be your entire nullspace.

I think you can get it from there!
 
Rellek said:
Remember that the nullspace is the set of all vectors that would send your original system to the zero vector.
Slight correction: the nullspace is the set of all vectors that your matrix would map to the zero vector.
Rellek said:
If you could find a set of vectors that are independent and send your system to the zero vector, then it seems as though the span of those vectors would be your entire nullspace.

I think you can get it from there!
 

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