Finding the Operational Determinant for a Differential Equation

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To find the operational determinant for the given differential equations, first rearrange the equations to group all terms involving x and y on one side. This results in the forms (D-4)x + 3y = 2t and 2x + (D-1)y = 0. The differential operator "D" can then be factored out from the differentials. This approach clarifies the process of finding the operational determinant and sets the stage for solving the equations. The user expressed gratitude for the guidance and plans to attempt the problem again later.
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Homework Statement


This is a problem in differential equations.

Find the operational determinant and solve the equation.

x'= 4x + y + 2t

y' = -2x + y

Homework Equations


The Attempt at a Solution



I'm at a total loss. All the examples in the book have problems with the form:

(D - 4)x + 3y = 0
-6x + (D + 7)y = 0

Nothing like what I have, and certainly nothing with x,y, AND t. That t really throws me off.
 
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jinksys said:

Homework Statement


This is a problem in differential equations.

Find the operational determinant and solve the equation.

x'= 4x + y + 2t

y' = -2x + y

Homework Equations


The Attempt at a Solution



I'm at a total loss. All the examples in the book have problems with the form:

(D - 4)x + 3y = 0
-6x + (D + 7)y = 0

Nothing like what I have, and certainly nothing with x,y, AND t. That t really throws me off.
First when doing these problems put all the xs and ys on one side of the equations.
So first you'll have
x'-4x - y = 2t
2x + y' - y = 0

Now factor the differential operator "D" from the differentials. (I'm assuming x and y are functions of t)

(D-4)x + 3y = 2t
2x + (D-1)y = 0

This gives you a way to find the operational determinant. To solve for a general solution you'll have to work a little more.
Try the problem now..
 
Last edited:
Thanks, it's much more clear now. I'll give the problem another try later.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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